<span>y'' + 5y' + 6y = 2e^t is a second order differential equation with solution y = Ae^mt + Be^nt + p(t); where m and n are the roots of the quadratic equation x^2 + 5x + 6 = 0, and p(t) is the particular solution.
x = -2 and x = -3
y = Ae^-2t + Be^-3t + p(t)
For the particular solution, Ke^t + 5Ke^t + 6Ke^t = 2e^t
12K = 2
K = 1/6
Therefore, solution is </span>
<span>y = Ae^-2t + Be^-3t + 1/6 e^t
</span>
Answer: The answer to 2c+15cd+9d+12=12.
Answer:
A) A rectangle with a length of 9 cm and a width of 3 cm
Step-by-step explanation:
The length to width ratio for the given rectangle is ...
21 cm : 7 cm = 3 : 1
Any similar rectangle will have the same ratio of length to width.
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For the offered choices, the ratios are ...
9:3 = 3:1 . . . . this is the answer
20:10 = 2:1
18:9 = 2:1
27:3 = 9:1
The answer is 2.5 just set it up and cross multiply then divide
Answer:
7.571
Rounded to the nearest 0.001 aka the Thousandths Place.