Answer:
V = 34,13*π cubic units
Step-by-step explanation: See Annex
We find the common points of the two curves, solving the system of equations:
y² = 2*x x = 2*y ⇒ y = x/2
(x/2)² = 2*x
x²/4 = 2*x
x = 2*4 x = 8 and y = 8/2 y = 4
Then point P ( 8 ; 4 )
The other point Q is Q ( 0; 0)
From these two points, we get the integration limits for dy ( 0 , 4 )are the integration limits.
Now with the help of geogebra we have: In the annex segment ABCD is dy then
V = π *∫₀⁴ (R² - r² ) *dy = π *∫₀⁴ (2*y)² - (y²/2)² dy = π * ∫₀⁴ [(4y²) - y⁴/4 ] dy
V = π * [(4/3)y³ - (1/20)y⁵] |₀⁴
V = π * [ (4/3)*4³ - 0 - 1/20)*1024 + 0 )
V = π * [256/3 - 51,20]
V = 34,13*π cubic units
Answer:
3x +8y = -17
Step-by-step explanation:
The point-slope equation is a good place to start.
y -k = m(x -h) . . . . . equation through (h, k) with slope m
Filling in your numbers gives ...
y +4 = -3/8(x -5)
Multiplying by 8, we get
8y + 32 = -3x + 15
Adding 3x-32 puts this in standard form.
3x + 8y = -17
_____
Standard form is ...
ax +by = c
where a, b, c are mutually-prime integers and the leading coefficient is positive. (If a=0, the leading coefficient is b.)
The distance between these points are 6
Answer:
Step-by-step explanation:
Differentiating, you get ...
... x·dy +y·dx +dx +dy = 2x·dx +2y·dy
Collecting terms gives ...
... dy(x +1 -2y) = dx(2x -y -1)
... dy/dx = -(2x -y -1)/(2y -x -1)
Answer:
Slope is 1
Step-by-step explanation:
Thus, the slope of the equation is 1
