Answer: −(b+4)(2b−3)
Step-by-step explanation:
1. Factor out the negative sign.
−(2b^2+5b−12)
2. Split the second term in 2b^2+5b−12 into two terms.
−(2b^2+8b−3b−12)
3.Factor out common terms in the first two terms, then in the last two terms.
−(2b(b+4)−3(b+4))
4. Factor out the common term b+4b+4b+4.
−(b+4)(2b−3)
Greater than 90° but less than 180°.
We're going to solve each of the systems to determine the solution.
<u>System
</u>

using a graph tool
the solution is the line 
see the attached figure N 
<u>System
</u>

using a graph tool
the solution is the shaded area
see the attached figure N 
<u>System
</u>

using a graph tool
The system has no solution
see the attached figure N 
<u>System
</u>

using a graph tool
the solution is the shaded area
see the attached figure N 
therefore
<u>the answer is</u>
<u>System
</u>

Given that the hot chocolate is made of 480 grams of milk and 20 grams of cacao.
We need to determine the percentage of cacao in hot chocolate.
<u>The percentage of cacao:</u>
The total grams of hot chocolate can be determined by adding the total grams of milk and the total grams of cacao.
Total grams of hot chocolate = Grams of Milk + Grams of cacao
Total grams of hot chocolate = 480 + 20 = 500 grams.
Thus, the total grams of hot chocolate is 500 grams.
Now, we shall find the percentage of cacao.
The percentage of cacao is given by

Simplifying, the values, we get,

Thus, the percentage of cacao is 4%
The product of this is 81