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alexdok [17]
3 years ago
6

Simplify 13 over the quantity of negative 3 plus 2i.

Mathematics
1 answer:
QveST [7]3 years ago
7 0

13

−

3

+

2

i

Multiply by

−

3

−

2

i

−

3

−

2

i

to make the denominator of

13

−

3

+

2

i

real.

13

−

3

+

2

i

−

3

−

2

i

−

3

−

2

i

Combine.

13

(

−

3

−

2

i

)

(

−

3

+

2

i

)

(

−

3

−

2

i

)

Expand

(

−

3

+

2

i

)

(

−

3

−

2

i

)

using the FOIL Method.

Tap for more steps...

13

(

−

3

−

2

i

)

−

3

⋅

−

3

−

3

(

−

2

i

)

+

2

i

⋅

−

3

+

2

i

(

−

2

i

)

Simplify.

Tap for more steps...

13

(

−

3

−

2

i

)

9

−

4

i

2

Simplify each term.

Tap for more steps...

13

(

−

3

−

2

i

)

9

+

4

Reduce the expression by cancelling the common factors.

Tap for more steps...

−

3

−

2

i

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3 years ago
7x + 8y = 25 9x + 10y =35 elimination method please​
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7x +8y = 25 ~~~....(i)\\\\9x +10y = 35~~~ ....(ii)\\\\\text{Multiply equation (ii) by}~ \dfrac 79 ~ \text{and do (ii) - (i):}\\\\\dfrac 79 (9x +10y) - (7x +8y) = \dfrac 79 (35) - 25\\\\\\\implies 7x +\dfrac{70y}9 - 7x -8y = \dfrac{245}9 -25\\\\\\\implies - \dfrac{2y}9 =  \dfrac{20}9\\\\\\\implies -2y =20\\\\\implies y =-10\\\\\text{Substitute}~ y = -10~ \text{in equation (i):}\\\\\\7x +8(-10) = 25\\\\\implies 7x  = 25 +80\\\\\implies 7x = 105 \\\\\implies x =15\\\\

\\\text{Hence}~ (x,y) = (15,-10)

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