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Lelu [443]
3 years ago
12

If Trent has 11 quarters and dimes in his pocket, and they have a combined value of 200 cents, how many of each coin does he hav

e?
Mathematics
1 answer:
allsm [11]3 years ago
4 0

Answer:

Trent has 6 quarters and 5 dimes.

Step-by-step explanation:

Consider the provided information.

Let q =  Number of quarters

d = Number of dimes.

Trent has 11 quarters and dimes.

q+d=11

q=11-d

The worth of a quarter is 25 cents.

The worth of a dimes is 10 cents

25q+10d=200

Substitute the value of q in above equation.

25(11-d)+10d=200

275-25d+10d=200

15d=75  

d=5  

Substitute the value of d in q=11-d

q=11-5

q=6

Hence, Trent has 6 quarters and 5 dimes.

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Which list is in order from least to greatest? A) 9.4 * 10^-8, 9.25 * 10^-6, 2.5 * 10^3, 7* 10^3 B) 2.5 *10^3, 7 * 10^3, 9.25 *
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