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Doss [256]
4 years ago
8

What are the solutions to the equation 3(x - 4)(x + 5) = 0?

Mathematics
1 answer:
Advocard [28]4 years ago
8 0

Answer:

Step-by-step explanation:

3(x - 4)(x + 5) = 0

Dividing through by 3

(x - 4)(x + 5) = 0

(x - 4) = 0 or x + 5 = 0

x - 4 = 0 or x + 5 = 0

x = 4 or x = - 5

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Rozalie spent $26 at a parking garage in downtown Orlando. The garage charged a base free of $7.50 for the first hour and a hour
bagirrra123 [75]
ANSWER : Rozalie spent 6.73 hours at the garage


rate of change = $2.75
base fee = $7.50

set up your equation:
2.75h + 7.5 = 26
($2.75/hour plus the base fee of $7.50 equals the total amount spent, $26)

Now just solve for h

2.75h + 7.5 = 26
2.75h = 18.5
h = 6.727273 (rounded)
h = 6.73

So the answer would be Rozalie spent about 6.73 hours at the garage.

6 0
3 years ago
Easy question i will mark braineliest
Yuki888 [10]

Answer:

<h2>0.67</h2>

Step-by-step explanation:

5(y - 3.8) = 4.7(y - 4)

Distribute 5 through the parentheses

5y - 19 = 4.7(y - 4)

Distribute 4.7 through the parentheses

5y - 19 = 4.7y - 18.8

Move ' 4.7 y ' to L.H.S and change it's sign

5y - 4.7y - 19 =  - 18.8

Move constant to R.H.S and change it's sign

5y - 4.7y =  - 18.8 + 19

Collect like terms

0.3y =  - 18.8 + 19

Calculate

0.3y = 0.2

Divide both sides of the equation by 0.3

\frac{0.3y}{0.3}  =  \frac{0.2}{0.3}

Calculate

y = 0.67

Hope this helps...

Best regards!!

3 0
3 years ago
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What is the geometric mean of 7 and 9.
kirza4 [7]
<span>√63 = 3√7  is your answer</span>
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If two triangles are congruent, which of the following statements must be true? Check all that apply.
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When figures are congruent, they have the same shape and size. All measures of one of the figures are identical to the corresponding measures of the other.

Of these statements, the following must be true ...

  • B. The corresponding sides of the triangles are congruent
  • C. The corresponding angles of the triangles are congruent
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5 0
3 years ago
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Use Cramer’s Rule to solve system of equation.
alisha [4.7K]

\left\{\begin{array}{ccc}5x+2y=4\\3x+4y+2z=6\\7x+3y+4z=29\end{array}\right\\\\A=\left[\begin{array}{ccc}5&2&0\\3&4&2\\7&3&4\end{array}\right]\\\\\det A=5\cdot4\cdot4+3\cdot3\cdot0+2\cdot2\cdot7-7\cdot4\cdot0-3\cdot2\cdot5-3\cdot2\cdot4=54\\W_x=\left[\begin{array}{ccc}4&2&0\\6&4&2\\29&3&4\end{array}\right]\\\det W_x=4\cdot4\cdot4+2\cdot2\cdot29+6\cdot3\cdot0-29\cdot4\cdot0-3\cdot2\cdot4-6\cdot2\cdot4=108

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5 0
3 years ago
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