I need help on number 9
1 answer:
You might be interested in
Answer:
Step-by-step explanation:
We want to solve the equation:
In the interval [0, 2π).
Notice that this is in quadratic form. Namely, by letting u = sin(θ), we acquire:
Factor:
By the Zero Product Property:
Solve for each case:
Back-substitute:
Use the Unit Circle. Hence, our three solutions in the interval [0, 2π) are:
Answer:
relation of FDs are {a, b, d, h}. From these all but {h}
seem plausibly part of keys. Calculating the closures of likely candidates gives:
{a, b} + = {a b, c, i}
{b, d} + = {b, d, e, f}
{a, d} + = {a, d, g, h, i, j}
{a, b, d} + = {a, b, c, d, e, f, g, h, i, j}
decompose r into 2nf and then 3nf relations shown in attachment.
Step- by-Step Explanation
Explanation is given in the attachment.
