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3 years ago

9

Lesson 6.04 in this lesson you will: 1. write the introdcution paragraph for your argument using the same topic you chose and re

searched in lesson 6.02.

1 answer:

mamaluj [8]3 years ago

5 0

What was ur lesson about???

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Solve the system of equations using multiplication. 3x – 3y = –3 5x – y = –13 What is the solution of the system?

love history [14]

ANSWER

The solution is

x=-3,y=-2

EXPLANATION

First equation

3x – 3y = –3

Second Equation:

5x – y = –13

Multiply the second equation by 3 to get:

Third equation:

15x-3y=-39

Subtract the first equation from the third equation:

$15x - 3x = - 39 - - 3$

$12x = - 36$

Divide both sides by 12,

$x = \frac{ - 36}{12} = - 3$

Put x=-3 into the first equation:

$3( - 3) - 3y = - 3$

$- 9 - 3y = - 3$

Group like terms,

$- 3y = - 3 + 9$

$- 3y = 6$

$y = - 2$

The solution is

x=-3,y=-2

6 0

3 years ago

3. Arrange these numbers from least to greatest. <br> -2.5<br> -1/3 1.7 27/4 -0.9

Svet_ta [14]

Answer: -2.5,, -0.9,, -1/3,, 1.7,, 27/4

Step-by-step explanation:

6 0

3 years ago

Subtract.<br> (6x + 5) - (x+3)

Roman55 [17]

(6x+5)-(x+3).

6x+5-x-3.

Add the like terms.

6x-x+5-3.

We get.

5x+2.

6 0

3 years ago

Read 2 more answers

147 is 3/2 of an original amount. What is the original amount

Dovator [93]

Answer:

98

Step-by-step explanation:

147/3=49x2=98

8 0

3 years ago

Help me with this!!!!!!

sveta [45]

Answer:

<em>IJ = 82</em>

Step-by-step explanation:

IJ≅IH so they are the same length

IH = 82 = IJ

6 0

3 years ago