Answer:
See below in bold.
Step-by-step explanation:
Let the length of the shortest side be x, then the longest side = 2x.
Also x + y = 2x + 1 where y = length of the middle side,
Simplifying:
2x - x - y = -1
x - y = -1 (A)
Also as the perimeter = 7:
x + 2x + y = 7
3x + y = 7 (B)
Adding (A) and (B):
4x + 0 = 6
x = 6/4 = 1.5
Plug x = 1.5 into equation B:
3(1.5) + y = 7
y = 7 - 4.5 = 2.5.
Answer:
So the shortest side = 1.5, middle = 2.5 and longest = 2*1.5 = 3.
Answer: the first answer choice
Step-by-step explanation:
Basically what you are doing is trying to find the square root of 8. What you need to do is find what would go into the number 8 equally so, you are basically finding the multiples
Answer:
y = -3x + 7
Step-by-step explanation:
Choosing two points from the given table:
Let (x1, y1) = (-3, 16)
(x2, y2) = (-1, 10)
Plug these given values into the slope formula:
m = (y2 - y1)/(x2 - x1)
= (10 - 16) / (-1 - (-3))
= -6 / (-1 + 3)
= -6/2
= -3
Therefore, the slope is -3.
Next, choose one of the points and plug into the <u>point-slope form</u>:
Let's use (-1, 10) as (x1, y1):
y - y1 = m(x - x1)
y - 10 = -3(x - (-1))
y - 10 = -3(x + 1)
y - 10 = -3x - 3
Add 10 on both sides to isolate y:
y - 10 + 10 = -3x - 3 + 10
y = -3x + 7
Answer:
The shadow is decreasing at the rate of 3.55 inch/min
Step-by-step explanation:
The height of the building = 60ft
The shadow of the building on the level ground is 25ft long
Ѳ is increasing at the rate of 0.24°/min
Using SOHCAHTOA,
Tan Ѳ = opposite/ adjacent
= height of the building / length of the shadow
Tan Ѳ = h/x
X= h/tan Ѳ
Recall that tan Ѳ = sin Ѳ/cos Ѳ
X= h/x (sin Ѳ/cos Ѳ)
Differentiate with respect to t
dx/dt = (-h/sin²Ѳ)dѲ/dt
When x= 25ft
tanѲ = h/x
= 60/25
Ѳ= tan^-1(60/25)
= 67.38°
dѲ/dt= 0.24°/min
Convert the height in ft to inches
1 ft = 12 inches
Therefore, 60ft = 60*12
= 720 inches
Convert degree/min to radian/min
1°= 0.0175radian
Therefore, 0.24° = 0.24 * 0.0175
= 0.0042 radian/min
Recall that
dx/dt = (-h/sin²Ѳ)dѲ/dt
= (-720/sin²(67.38))*0.0042
= (-720/0.8521)*0.0042
-3.55 inch/min
Therefore, the rate at which the length of the shadow of the building decreases is 3.55 inches/min
