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3 years ago

Help me please with this

Mathematics

1 answer:

AysviL [449]3 years ago

8 0

Since both angle are congruent (equal/same), which means that both side is equal to 40 degrees, we will put the equation like this:

5x - 5 = 40

Now we’ll solve for x:

5x - 5 = 40
+ 5 + 5 (Add 5 to both sides)

5x = 45
—- —— (Five both side by 5)
5 5

x = 9

Now we left with x, so x is equal to 9.

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Answer this please help needed

klasskru [66]

3.√(27x^9) = (27x^9)^(1/3) = 3x^3

8 0

3 years ago

Please help! find the value of x

Serga [27]

I needed points sorry

4 0

2 years ago

Read 2 more answers

7. For homework Javier has to solve the equation below.

cricket20 [7]

Answer:

C 10⁴

Step-by-step explanation:

The given equation is

$7.75n = 77500$

Javier has to solve for n

He can multiply through by 100 to get;

$775n = 7750000$

He can now divide through by 775 to obtain:

$n = \frac{7750000}{775}$

He can now easily simplify to get:

$n = 10000$

We rewrite as a power to get:

$n = {10}^{4}$

7 0

3 years ago

A chicken farmer also has cows for a total of 30 animals, and the animals have 66 legs in all. How many chickens does the farmer

hammer [34]

Answer:

27 chickens

Step-by-step explanation:

A chicken farmer also has cows for a total of 30 animals

Both animals have a total of 66 legs

Let a represent the number of chicken

Let b represent the number of cows

a + b= 30........equation 1

Since a chicken has only two legs and a cow has four leg then, the expression can be represented as

2a + 4b= 66........equation 2

From equation 1

a + b= 30

a = 30-b

Substitute 30-b for a in equation 2

2a + 4b= 66

2(30-b) + 4b= 66

60 - 2b + 4b= 66

60 + 2b= 66

2b= 66-60

2b= 6

b= 6/2

b= 3

Substitute 3 for b in equation 1

a + b = 30

a + 3=30

a= 30-3

a= 27

Hence the farmer has 27 chickens

5 0

3 years ago

A landscaper has 10 2/5 cubic yards of peat moss in a truck. If he unloads 2 2/3 cubic yards at the first site and 2 1/4 cubic y

Vikentia [17]

Step-by-step explanation:

The problem bothers on fractions, here we are being presented with mixed fractions.

what we are going to do bascially is to subtract the sum of all the uloaded

peat moss in sites 1 and 2 to get from the peat moss to get the remaining for the third site

therefore

$10\frac{2}{5}-(2\frac{2}{3}+ 2\frac{1}{4})$

we then have to convert the mixed fraction to further simplify the problem we have

$\frac{52}{5}-(\frac{8}{3}+ \frac{9}{4})$

we then solve the fraction to the right of the negative symbol first

$=\frac{52}{5}-(\frac{8}{3}+ \frac{9}{4})\\\\=\frac{52}{5}-\frac{32+27}{12} \\\\=\frac{52}{5}-\frac{59}{12} \\\\\=\frac{624-295}{60} \\\\=\frac{329}{60}$

We can now convert to mixed fraction

$=\frac{329}{60}\\\\ =5\frac{12}{25}$

For the third site the remainder is 5 12/25

8 0

3 years ago