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2 years ago

Did I do the reasons right?

Mathematics

2 answers:

erastovalidia [21]2 years ago

7 0

Answer: i'm sure its corrrect

andrew-mc [135]2 years ago

6 0

Im pretty sure that its correct you did good good job

You might be interested in

What is the measure of angle 1?

tatiyna

Answer:

27 degrees

Step-by-step explanation:

The easy way is by remembering the formula (a-b)/2=c, where a is the larger angle, and b is the smallest angle. (90-36)/2=27.

The longer, more drawn out answer goes as follows. See the image to understand the notation I use:

AOE + BOD + BOA + DOE = 360
AOE + BOD = 90 + 36 = 126
BOA + DOE = 360 - AOE - BOD = 234
Since the sum of a triangle's angles is 180, ODE = (180 - DOE) / 2
Likewise, OBA = (180 - BOA) / 2
Since CDE is 180, CDO = 180 - ODE = 180 - (180 - DOE) / 2
Likewise, CBA is 180, so CBO = 180 - OBA = 180 - (180 - BOA) / 2
The interior angles of the irregular polygon CBOD add up to 360, so CBO + CDO + BOD + BCD = 360.
Substituting what we already found, 180 - (180 - BOA)/2 + 180 - (180 - DOE)/2 + 36 + BCD = 360
Cleaning it all up, we get 180 + (BOA + DOE)/2 + 36 + BCD = 360
As we found in line 3, BOA + DOE = 234, so substituting that in, 180 + 117 + 36 + BCD = 360
Finally, solving for BCD (360 - 36 - 117 - 180) we get our answer, 27

Note: The long drawn out method shown above is a way to derive the formula for the secant theorem. You do not need to use this method every time. Just remember, large angle minus small angle, all divided by 2. That is it.

5 0

2 years ago

Sergio [31]

Answer:

39°F

Step-by-step explanation:

yeah thats is JDJDJDJDNSMS

5 0

2 years ago

Read 2 more answers

POS

meriva

Answer:

0.08 = 8%

2.3= 230%

0.34= 34%

1.05= 105%

0.7= 70%

0.049= 4.9%

7 0

3 years ago

What is the square root of -2i?

Studentka2010 [4]

Answer:

1-i and -1+i

Step-by-step explanation:

We are to find the square roots of $z=0-2i$ . First, convert from Cartesian to polar form:

$r=\sqrt{a^2+b^2}\\r=\sqrt{0^2+(-2)^2}\\r=\sqrt{0+4}\\r=\sqrt{4}\\r=2$

$\theta=tan^{-1}(\frac{b}{a})\\ \theta=tan^{-1}(\frac{-2}{0})\\\theta=\frac{3\pi}{2}$

$z=2(\cos\frac{3\pi}{2}+i\sin\frac{3\pi}{2})$

Next, use the formula $\displaystyle \sqrt[n]{r}\biggr[\cis\biggr(\frac{\theta+2\pi k}{n}\biggr)\biggr]$ where $\displaystyle k=0,1,2,...\:,n-1$ to find the square roots:

When k=1

$\displaystyle \sqrt[2]{2}\biggr[cis\biggr(\frac{\frac{3\pi}{2}+2\pi(1)}{2}\biggr)\biggr]$

$\displaystyle \sqrt{2}\biggr[cis\biggr(\frac{3\pi}{4}+\pi\biggr)\biggr]$

$\sqrt{2}\biggr(cis\frac{7\pi}{4}\biggr)$

$\sqrt{2}(\cos\frac{7\pi}{4}+i\sin\frac{7\pi}{4})\\ \\\sqrt{2}(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i)\\ \\1-i$

When k=0

$\displaystyle \sqrt[2]{2}\biggr[cis\biggr(\frac{\frac{3\pi}{2}+2\pi(0)}{2}\biggr)\biggr]$

$\sqrt{2}\biggr(cis\frac{3\pi}{4}\biggr)$

$\sqrt{2}(\cos\frac{3\pi}{4}+i\sin\frac{3\pi}{4})\\ \\\sqrt{2}(-\frac{\sqrt{2}}{2}+\frac{\sqrt{2}}{2}i)\\ \\-1+i$

Thus, the square roots of -2i are 1-i and -1+i

4 0

1 year ago

Part A

Deffense [45]

Answer: Not safe

Step-by-step explanation:

Let the angle of elevation of the ramp be θ, then:

$\begin{aligned}&\sin \theta=\frac{1.5}{10}=0.15 \\&\theta=\sin ^{-1}(0.15) \approx 8.63^{\circ}\end{aligned}$

But the maximum angle for the ramp cannot exceed 7.1°. The calculated angle of elevation will make it difficult, if not impossible, for motorized wheelchairs to get up the ramp.

Therefore, the ramp at the local library is not safe for motorized wheelchairs

5 0

2 years ago