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3 years ago

Y = (5 x 9) + 1 X 9) = 54

Mathematics

1 answer:

Viefleur [7K]3 years ago

5 0

Answer:

Step-by-step explanation:

1. Given that: y = (5 x 9) + (1 x 9)

= 45 + 9

= 54

Using repeated reasoning;

y = (5 x 9) + (1 x 9)

factoring 9 in the equation, we have;

y = 9 (5 + 1)

= 9 (6)

= 54

2i. 7 x 6 = (5 x 6) + (2 x 6)

= (5 + 2)6

= 7 x 6

= 42

ii. 7 x 9 = (5 x 9) + (2 x 9)

= (5 + 2)9

= 7 x 9

= 63

iii. 7 x 7 = (5 x 7) + (2 x 7)

= (5 + 2)7

= 7 x 7

= 49

Therefore, the factors that Pam used repeatedly are 5 and 2.

3. 7 x 8 = (LX) + (LX)

= X(L + L)

Representing L and X by a number,

7 x 8 = (4 x 7) + (4 x 7)

= 7(4 + 4)

= 7(8)

= 7 x 8

= 56

Thus, the generalization is true.

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Solve the equation. Then check your solution

kondaur [170]

Answer:

Option B is correct i.e. 21

Step-by-step explanation:

In the question we're provided with an equation that is :

v/7 = 3

And we are asked to find the solution for the equation .

Solution : -

 $\longrightarrow \: \frac{v}{7} = 3$ 

Multiplying by 7 on both sides :

$\longrightarrow \: \frac{v}{ \cancel{7} }\times \cancel{7} = 3 \times 7$

On further calculations , we get :

$\longrightarrow \: \blue{\boxed{v = 21}}$

Therefore , solution for equation is 21 .That means option B is the correct answer.

Verifying :

We are verifying our answer by substituting value of v in the equation given in question :

$\longrightarrow \: \frac{v}{7} = 3$

Putting value of v :

$\longrightarrow \: \cancel{\frac{21}{7}} = 3$

By dividing 21 with 7 , we get :

$\longrightarrow \:3 = 3$

$\longrightarrow \: L.H.S=R.H.S$

$\longrightarrow \: Hence , \: Verified.$

Therefore , our answer is valid .

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Assume that a procedure yields a binomial distribution with a trial repeated n times. Use the binomial probability formula to fi

Keith_Richards [23]

Answer:

P(X = 12) = 0.0064.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$n = 30, p = 0.2$

We want P(X = 12). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 12) = C_{30,12}.(0.2)^{12}.(0.8)^{18} = 0.0064$

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Bezzdna [24]

Answer:

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Step-by-step explanation:

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Let c be the cost,

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