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inessss [21]
3 years ago
13

How many ordered pairs of positive integers satisfy xY=32?

Mathematics
1 answer:
IRINA_888 [86]3 years ago
4 0

Answer:


Step-by-step explanation:

xy = 32

x ; y is the divisor of 32

but : 32 =  2^5

6  ordered pairs of positive integers satisfy xY=32

(1;32) , (2;16) , (4; 8),(32; 1) , (16;2) , (8;4) .

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Set up two equations:

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Divide both sides by 15:

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J = 20

Jenkins used theirs for 20 hours

Price used theirs for 45-20 = 25 hours.

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Answer:

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Step-by-step explanation:


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3 years ago
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