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Andre45 [30]
3 years ago
10

Apply the markup for each item. Then, find the retail price. Round to two decimals places when necessary.

Mathematics
1 answer:
Alborosie3 years ago
7 0

Answer:

$45 with 20% markup = $45 + $9 for a new total = $54

$7.60 with a 50% markup = $7.60 + $3.80 for new total = $11.40

Step-by-step explanation:


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The ratio of the side lengths of a quadrilateral is 3:2:6:7, and its perimeter is 126 meters. What is the length of the shortest
scoundrel [369]

since the lengths of all those four sides are in a 3:2:6:7 ratio, and the whole perimeter is 126, what we do is, simply divide the whole by (3+2+6+7) and distribute accordingly.


\bf \stackrel{3\cdot \frac{126}{3+2+6+7}}{3}~~:~~\stackrel{2\cdot \frac{126}{3+2+6+7}}{2}~~:~~\stackrel{6\cdot \frac{126}{3+2+6+7}}{6}~~:~~\stackrel{7\cdot \frac{126}{3+2+6+7}}{7} \\\\\\ 3\cdot \cfrac{126}{18}~~:~~2\cdot \cfrac{126}{18}~~:~~6\cdot \cfrac{126}{18}~~:~~7\cdot \cfrac{126}{18} \\\\\\ 21~~:~~\stackrel{shortest}{14}~~:~~42~~:~~49

7 0
3 years ago
Please help, I have answered 74 questions and I still have other work to do.
Genrish500 [490]

Answer:

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Step-by-step explanation:

Mwah there lol <3

Hope it helps

6 0
2 years ago
Plzzzzzzzzzzzzzzzzzzzzzz find the hcf of 15a²b² and -24ab
Ad libitum [116K]

Let's take a look at each term separately.

15a^2b^2:

15 has factors 1, 3, 5, 15

a x a

b x b

-24ab

-24 has factors 1, 2, 3, 4, 6, 8, 12, 24

a

b

Now, we can see what each of these terms has in common. Both have a 3 in their factor lists, as well as one a and one b.

Therefore, the greatest common factor is 3ab.

Hope this helps!! :)

7 0
3 years ago
Read 2 more answers
I will breann list yuo
solmaris [256]
I would 9/4 seeming you have to do devision with this also
6 0
2 years ago
Read 2 more answers
umuc stat club must appoint a president. a vice president and a treasurer. There are 8 qualified candidates. How many different
zalisa [80]
The best possible solution for this item is to determine the permutation of 8 taken 3 since there are 3 positions and 8 people are qualified. We will use permutation instead of combination because of the specificity of the positions. That is,
                                 8P3 = 336
Thus, there are 336 ways in which the officers can be selected. 
5 0
3 years ago
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