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3 years ago

14

The image of the ant is 9 times the ant's actual size and has a length of 1.8 cm.

1 answer:

Rom4ik [11]3 years ago

4 0

Answer:

0.2 is the correct asnwer because you divide 1.8 by 9

Step-by-step explanation:

I hope this helps you:) Please mark brainliest if correct:)

Stay safe, God bless and happy studying!

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Robert wants to use all the ingredients listed in the table at the right to make trail mix. How many ½ -lb packages can he make?

lara31 [8.8K]

Answer:

16 half packages.

Step-by-step explanation:

You basically need to add them all of the weight of each ingredients together, and then you multiply by 2.

4 0

3 years ago

Let m=x²-5. which equation is equivalent to (x²-5)²-3x²+15=-2 in term of m?

SpyIntel [72]

The answer would be m^2+3m+2=0 because the first “part” of the equation (x^2-5) is equal to m; in the equation it’s squared so it can be replaced by m^2. next, 3m is the same as 3(x^2+5) which is what you have when you see 3x^2+15. finally, you have to bring the -2 over from the other side so you have positive 2. hope this helps!

7 0

3 years ago

Solve for Y. 9/4y-12=1/4y-4

Lelechka [254]

I believe y equals 4.

9/4y - 12. = 1/4y - 4
+ 12. +12
9/4y. = 1/4y + 8
- 1/4y. - 1/4y

8/4y. = 8
2y. = 8
2. 2
Y = 4

4 0

3 years ago

Read 2 more answers

Prove each statement that is true and ﬁnd a counterexample for each statement that is false. Assume all sets are subsets of a un

tekilochka [14]

Answer with Step-by-step explanation:

We are given that A, B and C are subsets of universal set U.

We have to prove that

$A\cap (B-C)=(A\cap B)-(A\cap C)$

Proof:

Let x $\in A\cap (B-C)$

Then $x\in A$ and $x\in(B-C)$

When $x\in ( B-C)$ then $x\in B$ but $x\notin C$

Therefore, $x\in( A\cap B)$ but $x\notin (A\cap C)$

Hence, it is true.

Conversely , Let $x\in(A\cap B)$ but $x\notin(A\cap C)$

Then $x\in A$ and $x\in B$

When $x\notin ( A\cap C)$ then $x\notin C$

Therefor, $x\in A\cap (B-C)$

Hence, the statement is true.

5 0

3 years ago

Allen wants to have a mean of 90 on his math quizzes. So far, he has scored 86, 94, 88, 95, and 89. What is the least score that

viva [34]

Answer:

88

Step-by-step explanation:

$\frac{86 + 94 + 88 + 95 + 89 + x}{6} = 90$

The mean would be the sum of all the math quiz grades divided by the number of quizzes taken.

Solve for x:

$86 + 94 + 88 + 95 + 89 + x = 540$

$452 + x = 540$

$x = 88$

Thus, Allen needs at least an 88 to obtain a mean of at least 90.

3 0

3 years ago