6x+4y=2
3x+2y=1
If you multiply by 2 the second statement you'll get the first one which means they belong to the same graph (same line, lines are coincident). The system is consistent and dependent.
The answer is: C. coincident
Answer: Choice ARaising something to the 1/4th power is the same as applying the 4th root to that expression. Raising an expression to the 1/n power is the same as applying the nth root.
Rule:
![x^{1/n} = \sqrt[n]{x}](https://tex.z-dn.net/?f=x%5E%7B1%2Fn%7D%20%3D%20%5Csqrt%5Bn%5D%7Bx%7D%20)
(if the text is too small it basically says x to the (1/n) = square root with a small 'n' all over x)
Answer:
whyu
Step-by-step explanation:
whyu
Answer:
<h2><u><em>
1</em></u></h2>
Step-by-step explanation:
What is 1 over 4 + 3 over 4?
1/4 + 3/4 =
4/4 =
1
This is tricky. Fasten your seat belt. It's going to be a boompy ride.
If it's a 12-hour clock (doesn't show AM or PM), then it has to gain
12 hours in order to appear correct again.
How many times must it gain 3 minutes in order to add up to 12 hours ?
(12 hours) x (60 minutes/hour) / (3 minutes) = 240 times
It has to gain 3 minutes 240 times, in order for the hands to be in the correct positions again. Each of those times takes 1 hour. So the job will be complete in 240 hours = <em>10 days .</em>
Check:
In <u>10</u> days, there are <u>240</u> hours.
The clock gains <u>3</u> minutes every hour ==> <u>720</u> minutes in 240 hours.
In 720 minutes, there are 720/60 = <u>12 hours</u> yay !
_________________________________
If you are on a military base and your clocks have 24-hour faces,
then at the same rate of gaining, one of them would take 20 days
to appear to be correct again.
_________________________________
Note:
It doesn't have to be an analog clock. Cheap digital clocks can
gain or lose time too (if they run on a battery and don't reference
their rate to the 60 Hz power that they're plugged into).
