Question

What is the product of (3a + 2)(4a2 – 2a + 9)?

Answer 1

12*a^3 -6a^2 + 27a + 8a^2 -4*a +18 =
12*a^3 +2*a^2+23*a +18

Answer 2

Answer:

$12a^3 + 2a^2 + 23a +18$

Step-by-step explanation:

Given: We have given two expressions:  (3a + 2) and $(4a^2 - 2a + 9)$

We have to find the product of these expressions.

(3a + 2)($4a^2 -2a + 9)$

Now we have to use the distributive a(b + c) = a.c + a.c

3a($4a^2 -2a + 9) + 2(4a^2 -2a + 9)$

= $12a^3 - 6a^2 + 27a + 8a^2 - 4a + 18$

Now we can combine the like terms and simplify.

= $12a^3 -6a^2 + 8a^2 + 27a - 4a + 18$                  [-6a^2 + 8a^2 = 2a^2]

= $12a^3 + 2a^2 + 23a + 18$                                    [27a -4a = 23a]