You can turn 5 into 10/2 and add to x/2
then you need to use simple algebra to left the x alone in the equation so you need to multiply both sides by 2 so you get
2y=10+x
then you need to subtract both sides a 10 so
2y-10=x
now change the x to f'(x) and y to x so:
f'(x)=2x-10
Answer:
Part A) The area of the figure is 
Part B) The perimeter of the figure is 
Step-by-step explanation:
step 1
Find the area of the figure
we know that
The area of the figure is equal to the area of triangle ABD plus the area of triangle BCD
The area of triangle is equal to

<u>Area of triangle ABD</u>
Observing the graph


substitute

<u>Area of triangle BCD</u>
Observing the graph


substitute

The area of the figure is

step 2
Find the perimeter of the figure
we know that
The perimeter of the figure is equal to

we have

the formula to calculate the distance between two points is equal to
Find the distance AB
Find the distance BC
Find the distance CD
Find the distance AD
substitute the values

Pythagorean Theorem
3*3+8*8=x*x
9+64=x*x
73=x*x
x=√73≈8.5
Answer: 6.71
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Work Shown:
The longest horizontal portion of length 6 breaks up into two equal pieces of length 3 each. Focus on the smaller right triangle on the right hand side. This right triangle has legs of 3 and 6. The hypotenuse is x.
Use the pythagorean theorem with a = 3, b = 6, c = x to find the value of x
a^2 + b^2 = c^2
3^2 + 6^2 = x^2
9 + 36 = x^2
45 = x^2
x^2 = 45
x = sqrt(45)
x = 6.7082039
x = 6.71