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2 years ago

A square has a side length 9cm. What is its area in square centimeters?

Mathematics

1 answer:

-Dominant- [34]2 years ago

4 0

Answer:

Step-by-step explanation:

A square has all sides the same so you just multiply 9×9

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Sketch the graph of y=-2x² + x + 1 using your graphing calculator. What are the x-intercepts of this graph?

irakobra [83]

Answer is going to be A.

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3 years ago

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What time is 7 1/2 hours before 2:12 am

Advocard [28]

It's 7:18... Because you have to because 7 subtract 2:12 is 7, and half is 30 min...

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3 years ago

Hi I hope you are all okay could someone help me with this math question thankyou !!!

earnstyle [38]

Answer:

x = 49

Step-by-step explanation:

Given the mathematical expression and data;

y = 1/√x

y = 7 and x = 64

First of all, we would find the constant of proportionality, k;

y = k/√x

7 = k/√64

7 = k/8

k = 7 * 8

k = 56

Next, to find the value of x, when y = 8

y = k/√x

Substituting the values, we have;

8 = 56/√x

Cross-multiplying, we have;

8 * √x = 56

√x = 56/8

√x = 7

Taking the square of both sides, we have;

(√x)² = 7²

x = 49

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2 years ago

Solve the given equation. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to three decimal plac

Fed [463]

Answer:

$\theta=k\pi, \hspace{3}k\in Z\\\\ or\\\theta =2\pi k \pm arccos(\frac{1 }{8} ), \hspace{3}k\in Z\\$

Step-by-step explanation:

Factor constant terms:

$-2(-4sin(2\theta)+sin(\theta))=0$

Divide both sides by -2:

$sin(\theta)-4sin(2 \theta)=0$

Expand trigonometric functions using the fact:

$sin(2 \theta) =2 sin(\theta) cos(\theta)$

So:

$sin(\theta) -8sin(\theta)cos(\theta)=0$

Factor sin(x) and constant terms and multiply both sides by -1:

$sin(\theta) (8cos(\theta)-1)=0$

Split into two equations:

$(1)=8cos(\theta)-1=0\\\\(2)=sin(\theta)=0$

For (1)

Add 1 to both sides and divide both sides by 8:

$cos(\theta)=\frac{1}{8}$

Take the inverse cosine of both sides:

$\theta =2\pi k \pm arccos(\frac{1 }{8} ), \hspace{3}k\in Z$

For (2)

Simply take the inverse sine of both sides

$\theta = k \pi, \hspace{3}k\in Z$

Therefore, the solutions are given by:

$\theta=k\pi, \hspace{3}k\in Z\\\\ or\\ \theta =2\pi k \pm arccos(\frac{1 }{8} ), \hspace{3}k\in Z\\$

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3 years ago

Which polynomial is prime? x2 – 36 x2 + 16 x2 – 7x + 12 x2 – x – 20

juin [17]

Answer:

$x2 - 7x + 12$

Step-by-step explanation:

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3 0

2 years ago

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