Answer:
y=-3/2x+10
Step-by-step explanation:
Plug in the point and the slope to the point-slope form equation (y-y1=m(x-x1)), getting y-1=-3/2(x-6). Simplify. y-1=-3/2x+9. Add one to both sides to isolate y, therefore giving you slope-intercept form.
SA=2lw+2lh+2hw ..........
1.7n +1
I think the is the answer
I hope this helps :)
Answer:
y+3=45(x+5)
Step-by-step explanation:
Hi there!
Point-Slope Form:
y-y1=m(x-x1)
Where
y1 stands for the y-coordinate of the point
m stands for the slope of the line
x1 stands for the x-coordinate of the point
In this case, the slope is 45, the y-coordinate of the given point is -3, and the x-coordinate of the point is -5.
Plug in the values and solve:
y-y1=m(x-x1)
y-(-3)=45(x-(-5)
y+3=45(x+5)
Hope it helps!
Enjoy your day!
Please feel free to ask if you have any doubts.

Answer:
i believe the relative max coordinate is (2,4)
relative min is (-2,0) and (4,0)
and these are not absolute exterma maybe because there are more than one relative min?