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Nimfa-mama [501]
4 years ago
14

Please help and give correct awnser

Mathematics
1 answer:
Iteru [2.4K]4 years ago
5 0

Since each unit cube I gives the value of oneI would multiply 48x1.Your answer would be 48

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The graph of g(x), shown is a vertical shift of the graph of f(x)=2^x. Write the equation for g(x)
DaniilM [7]

Answer:

It's D .

Step-by-step explanation:

The graph of  f(x) = 2^x passes through the y axis at (0, 1).

The graph of g(x) passes through (0, 0) so g(x) = 2^x - 1.

4 0
3 years ago
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15) A rectangular yard has a length that is 5 feet more than the width. Around the outside of the yard is a path made of bricks
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Step-by-step explanation:

Ok so umm I literally have no idea or I’m too lazy but good luck

3 0
4 years ago
Find the missing measures for the rectangle
Vadim26 [7]
Do you have a picture or something to accompany the question? 
5 0
3 years ago
6 cm
Svetach [21]

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3 cm base 4 cm height

Step-by-step explanation:

6 0
3 years ago
An article gave the accompanying data on ultimate load (kN) for two different types of beams. Assuming the underlying distributi
krok68 [10]

Answer:

The 99% confidence interval for the difference between the true average load for the fiberglass beams and that for the carbon beams is (-11.937, -6.863).

Step-by-step explanation:

We have to calculate a 99% confidence interval for the difference between the true average load for the fiberglass beams and that for the carbon beams.

The sample 1 (Fiberglass), of size n1=26 has a mean of 33.4 and a standard deviation of 2.2.

The sample 2 (Carbon), of size n2=26 has a mean of 42.8 and a standard deviation of 4.3.

The difference between sample means is Md=-9.4.

M_d=M_1-M_2=33.4-42.8=-9.4

The estimated standard error of the difference between means is computed using the formula:

s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{2.2^2}{26}+\dfrac{4.3^2}{26}}\\\\\\s_{M_d}=\sqrt{0.186+0.711}=\sqrt{0.897}=0.9473

The critical t-value for a 99% confidence interval is t=2.678.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_{M_d}=2.678 \cdot 0.9473=2.537

Then, the lower and upper bounds of the confidence interval are:

LL=M_d-t \cdot s_{M_d} = -9.4-2.537=-11.937\\\\UL=M_d+t \cdot s_{M_d} = -9.4+2.537=-6.863

The 99% confidence interval for the difference between the true average load for the fiberglass beams and that for the carbon beams is (-11.937, -6.863).

8 0
4 years ago
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