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2 years ago

The three trigonometric functions can be used to calculate unknown side lengths and angles in which type of triangle(s)?

1 answer:

3 0

Using the three trigonometric functions can be used to calculate unknown side lengths and angle in a right-angle triangle only.

But, if ever you we're given to find a non right-angle triangle, you will have to use sine rule or cosine rule.

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3x-5y=60 4x+5y=-4 what is the system of linear equation

Sergeu [11.5K]

(3x-5y=60)

4x+5y=-4

3(8)-5(7.2)=60

4(8)+5(-7.2)=-4

7x=56

÷7. ÷7

x=8

3(8)-5y=60

4(8)+5y=-4

32+5y=-4

-32. -32

5y=-36

÷5. ÷5

y=7.2

4 0

2 years ago

Do you add or multiple?

BaLLatris [955]

Add your welcome I think

3 0

2 years ago

Question 5: prove that it’s =0

mamaluj [8]

Answer:

Proof in explanation.

Step-by-step explanation:

I'm going to attempt this by squeeze theorem.

We know that $\cos(\frac{2}{x})$ is a variable number between -1 and 1 (inclusive).

This means that $-1 \le \cos(\frac{2}{x}) \le 1$ .

$x^4 \ge 0$ for all value $x$ . So if we multiply all sides of our inequality by this, it will not effect the direction of the inequalities.

$-x^4 \le x^4 \cos(\frac{2}{x}) \le x^4$

By squeeze theorem, if $-x^4 \le x^4 \cos(\frac{2}{x}) \le x^4$

and $\lim_{x \rightarrow 0}-x^4=\lim_{x \rightarrow 0}x^4=L$ , then we can also conclude that $\im_{x \rightarrow} x^4\cos(\frac{2}{x})=L$ .

So we can actually evaluate the "if" limits pretty easily since both are continuous and exist at $x=0$ .

$\lim_{x \rightarrow 0}x^4=0^4=0$

$\lim_{x \rightarrow 0}-x^4=-0^4=-0=0$ .

We can finally conclude that $\lim_{\rightarrow 0}x^4\cos(\frac{2}{x})=0$ by squeeze theorem.

Some people call this sandwich theorem.

6 0

2 years ago

-8(2b-7)-9(b-5) simplify

GenaCL600 [577]

Answer:

Step-by-step explanation:

$-8(2b-7)-9(b-5)\qquad\text{use the distributive property:}\ a(b+c)=ab+ac\\\\=(-8)(2b)+(-8)(-7)+(-9)(b)+(-9)(-5)\\\\=-16b+56-9b+45\qquad\text{combine like terms}\\\\=(-16b-9b)+(56+45)\\\\=-25b+101$