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juin [17]
2 years ago
5

Write the following equation in standard form:22+52 +4 24 - 220

Mathematics
1 answer:
LekaFEV [45]2 years ago
6 0

Answer:2.78×10^2

Step-by-step explanation:

22+52+424-220

=278

In standard form

=2.78×10^2

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you had $4,982 in your checking account. then you wrote 4 checks for $786 each. how much money is left in your bank account
quester [9]

Answer:

$1826 left in the account.

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
The length of a rectangular mailing label is
trasher [3.6K]
P = 2(L + W)
P = 22
L = 2W - 4

22 = 2(2W - 4 + W)
22 = 2(3W - 4)
22 = 6W - 8
22 + 8 = 6W
30 = 6W
30/6 = W
5 = W.....width is 5 cm

L = 2W - 4
L = 2(5) - 4
L = 10 - 4
L = 6....length is 6 cm
3 0
2 years ago
Find the standard form of the equation of the parabola with a focus at (5, 0) and a directrix at x = -5.
Elena-2011 [213]
Let's notice, the focus is at (5,0) and the directrix at x = -5.

keep in mind that there's a distance "p" from the vertex to either of those fellows, therefore, if the focus is at 5,0 and the directrix x = -5, the vertex is half-way between them, check the picture below.

notice the distance "p" there, now, is a horizontal parabola, opening to the right, meaning the value for "p" is positive, or just 5, thus

\bf \textit{parabola vertex form with focus point distance}\\\\
\begin{array}{llll}
\boxed{(y-{{ k}})^2=4{{ p}}(x-{{ h}})}
\\\\
(x-{{ h}})^2=4{{ p}}(y-{{ k}})
\end{array}
\qquad 
\begin{array}{llll}
vertex\ ({{ h}},{{ k}})\\\\
{{ p}}=\textit{distance from vertex to }\\
\qquad \textit{ focus or directrix}
\end{array}\\\\
-------------------------------\\\\
\begin{cases}
h=0\\
k=0\\
p=5
\end{cases}\implies (y-0)^2=4(5)(x-0)\implies y^2=20x
\\\\\\
\cfrac{y^2}{20}=x\implies \cfrac{1}{20}y^2=x

8 0
3 years ago
Anyone willing to help me through out the whole rest of the questions ?
Ugo [173]
60/360 x 90 = 15

the answer is B
6 0
3 years ago
Please help!!!! I need this ASAP Help
Nutka1998 [239]

Answer:

Step-by-step explanation:

If x is -1, then the point on the parabol is (-1,4)

If x is 0, then the point on the parabol is (0,-2)

If x is 1, then the point on the parabol is (1,-6)

8 0
3 years ago
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