What is the equation of a line that is perpendicular to the line y = -3x + 2 and passes through the point (6,8)?
1 answer:
Answer:
y = 1/3x+6
Step-by-step explanation:
y = -3x+2 is in slope intercept form y = mx+b where m is the slope and b is the y intercept
The slope is -3
Perpendicular lines have slopes that are negative reciprocals
The slope of the perpendicular line is -1/-3 = 1/3
The equation of the new line is
y = 1/3x +b
Using the point that passes through the line ( 6,8) and substituting in for x and y
8 = 1/3(6) +b
8 = 2+b
8-2 =b
6 =b
The equation becomes
y = 1/3x+6
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Answer:
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Step-by-step explanation:
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Answer:
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Step-by-step explanation:
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