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Lemur [1.5K]
2 years ago
11

Find the coordinates of H' after a reflection across the parallel lines; first across y = -2 and then across y = 2. Answer in fo

rm (a,b). Part 7a
​

Mathematics
1 answer:
Harrizon [31]2 years ago
4 0

Answer: H' = (-4, 4)

<u>Step-by-step explanation:</u>

H = (-4, -4)

reflect across y = -2:

H is 2 units below y = -2 so when reflected it will be 2 units above y = -2

--> t<em>he x-coordinate doesn't change</em>    the new y-coordinate is: 0

H' = (-4, 0)

reflect across y = 2:

H' is 2 units below y = 2 so when reflected it will be 2 units above y = 2

--> t<em>he x-coordinate doesn't change</em>    the new y-coordinate is: 4

H'' = (-4, 4)

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32/21

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multiply (2/3) by (7/7) and (6/7) by (3/3). (14/21) + (18/21) is (32/21)

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I need helppp I’m stuck
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