Answer:
1)- Variable utilities cost per machine hour = 1.6 per machine hour
2)- Fixed cost = 1740
3)-Total cost on 1220 Machine hour will be
= 3692
Step-by-step explanation:
1) CALCULATE VARIABLE UTILITIES COST PER MACHINE HOUR :
Variable utilities cost per machine hour = Change in cost/high machine hour-low machine hour
=4076-3388/1460-1030
Variable utilities cost per machine hour = 1.6 per machine hour
2) Fixed cost = Total cost-variable cost
= 3388-(1030*1.6)
Fixed cost = 1740
3) Total cost on 1220 Machine hour will be (1220*1.6+1740) = 3692
P(4-4)=p(0)=0
0=0
true, they are equivilent
The value of the collection originally was $1,000,000
What was the original value of the collection?
The original value of the collection is not known, hence, it is represented by X
The increase in value by $50,000 means that the value is X+$50,000
Now, when the error was discovered, it is now worth half of the value previously
The new value is (X+$50,000)*0.5
New value=(X+$50,000)*0.5
The new value at this point is $525,000
$525,000=(X+$50,000)*0.5
$525,000/0.5=X+$50,000
$1,050,000=X+$50,000
X=$1,050,000-$50,000
Find out more about change in value on:brainly.com/question/13097163
#SPJ1
Answer:
Y= 2e^(5t)
Step-by-step explanation:
Taking Laplace of the given differential equation:
s^2+3s-10=0
s^2+5s-2s-10=0
s(s+5)-2(s+5) =0
(s-2) (s+5) =0
s=2, s=-5
Hence, the general solution will be:
Y=Ae^(-2t)+ Be^(5t)………………………………(D)
Put t = 0 in equation (D)
Y (0) =A+B
2 =A+B……………………………………… (i)
Now take derivative of (D) with respect to "t", we get:
Y=-2Ae^(-2t)+5Be^(5t) ....................... (E)
Put t = 0 in equation (E) we get:
Y’ (0) = -2A+5B
10 = -2A+5B ……………………………………(ii)
2(i) + (ii) =>
2A+2B=4 .....................(iii)
-2A+5B=10 .................(iv)
Solving (iii) and (iv)
7B=14
B=2
Now put B=2 in (i)
A=2-2
A=0
By putting the values of A and B in equation (D)
Y= 2e^(5t)
