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2 years ago

Which letter is in the solution set for graph #2

Mathematics

1 answer:

stealth61 [152]2 years ago

8 0

Answer:

Step-by-step explanation:

y > 0 - the region above the line together with that line

y ≥ 0 - the region above the line together with that line

y < 0 - the region below the line without that line

y ≤ 0 - the region below the line together with that line

We have:

y > 2 - the region above the line together with that line

y ≥ 2x - 3 - the region above the line together with that line

look at the picture

The common part is the solution.

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Dilate the segment about the origin by a scale factor of 1 /2 What are the coordinates of B'? please help

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(1,-2) edge2020

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2 years ago

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Which following not composite 45,35,41,33 and tell me how

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2 years ago

What is the quotient 36 divided by 6

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Answer:

Step-by-step explanation:

36/6

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3 years ago

Verify that P = Ce^t /1 + Ce^t is a one-parameter family of solutions to the differential equation dP dt = P(1 − P).

NemiM [27]

Answer:

See verification below

Step-by-step explanation:

We can differentiate P(t) respect to t with usual rules (quotient, exponential, and sum) and rearrange the result. First, note that

$1-P=1-\frac{ce^t}{1+ce^t}=\frac{1+ce^t-ce^t}{1+ce^t}=\frac{1}{1+ce^t}$

Now, differentiate to obtain

$\frac{dP}{dt}=(\frac{ce^t}{1+ce^t})'=\frac{(ce^t)'(1+ce^t)-(ce^t)(1+ce^t)'}{(1+ce^t)^2}$

$=\frac{(ce^t)(1+ce^t)-(ce^t)(ce^t)}{(1+ce^t)^2}=\frac{ce^t+ce^{2t}-ce^{2t}}{(1+ce^t)^2}=\frac{ce^t}{(1+ce^t)^2}$

To obtain the required form, extract a factor in both the numerator and denominator:

$\frac{dP}{dt}=\frac{ce^t}{1+ce^t}\frac{1}{1+ce^t}=P(1-P)$

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3 years ago

Triangle ABC is an isosceles right triangle inscribed in a circle. The center of the circle is point D and the diameter of the c

Paha777 [63]

Answer:

* AD is congruent to DC and BD true

* m∠B = 90° true

* The measure of arc AC is equal to the measure of arc AB not be true ( The right answer )

* The measure of arc AB is equal to measure of arc BC true

Step-by-step explanation:

∵ D is the center of the circle and A , B and C are points on the circle

∴ AD , DB and DC are radii on the circle D

∴ AD ≡ DC ≡ DB

∵ AC passing through point D which is the center of the circle

∴ AC is the diameter of the circle D

∵ ∠B is opposite to the diameter of the circle and vertex B lies on the circle

∵ ∠B is an inscribed angle and ∠ADC is a central angle subtended by the same arc AC

∴m∠B = half m∠ADC

∵ m∠ADC = 180°

∴ m∠B = 90°

∵ The measure of arc AC = 180°

∵ ΔABC is isosceles and m∠B = 90°

∴ m∠BAC = m∠BCA = (180° - 90°) ÷ 2 = 45°

∵ ∠ACB is an inscribed angle subtended by arc AB

∴ m∠ACB = half measure of arc AB

∵ The measure of arc AB = 45° × 2 = 90°

∴ The measure of arc AC ≠ the measure of arc AB

∵ Δ ABC is an isosceles triangle and m∠B = 90°

∴ AB = BC

∵ AB subtended by arc AB

∵ BC subtended by arc BC

∴ The length of arc AB = the length of arc BC

∵ If two arcs are equal in length, then they will be equal in measure

∴ The measure of arc AB is equal to the measure of arc BC

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3 years ago