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3 years ago

Which letter is in the solution set for graph #2

Mathematics

1 answer:

stealth61 [152]3 years ago

8 0

Answer:

Step-by-step explanation:

y > 0 - the region above the line together with that line

y ≥ 0 - the region above the line together with that line

y < 0 - the region below the line without that line

y ≤ 0 - the region below the line together with that line

We have:

y > 2 - the region above the line together with that line

y ≥ 2x - 3 - the region above the line together with that line

<em>look at the picture</em>

The common part is the solution.

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Someone please help me ASAP please anyone I need help now

irinina [24]

(2165-59)/3=
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8 0

3 years ago

Select the correct solution for the expression.<br><br> 2/5+3/8

igor_vitrenko [27]

Answer: 31/41

Explanation: You multiply the numerator and denominator across such as (2 and 8)= 16 and (3 and 5)= 15.

Once that done, you just calculate it together to get

=31/40

6 0

2 years ago

What is the rule for the reflection?

Step2247 [10]

<span>Reflection in the line y = x. A reflection in the line y = x can be seen in the picture below in which A is reflected to its image A'. The general rule for a reflection in the y-axis: (A, B) (B, A)</span>

4 0

3 years ago

Read 2 more answers

Write a quadratic function, in standard form, that fits the set of points. Solve it as a system of three equations. (-4, 9), (0,

Tresset [83]

Answer:

$\boxed{y=2x^2+4x-7}$

Step-by-step explanation:

Let the quadratic function be

$y=ax^2+bx+c$

We substitute $(-4,9)$ into the equation to obtain;

$9=a(-4)^2+b(-4)+c$

$\Rightarrow 9=16a-4b+c---(1)$

We substitute $(0,-7)$ to obtain;

$-7=a(0)^2+b(0)^2+c$

$\Rightarrow c=-7---(2)$

We finally substitute $(1,-1)$ to obtain;

$-1=a(1)^2+b(1)^2+c$

$\Rightarrow -1=a+b+c---(3)$

We put equation (2) into equation (1) to get;

$9=16a-4b-7$

$16a-4b=16$

$\Rightarrow 4a-b=4---(4)$

$\Rightarrow -1=a+b-7$

$\Rightarrow a+b=6---(5)$

We add equation (4) and (5) to get;

$4a+a=6+4$

$\Rightarrow 5a=10$

$\Rightarrow a=2$

We put $a=2$ into equation (5) to get;

$2+b=6$

$\Rightarrow b=6-2$

$\Rightarrow b=4$

The reqiured quadratic function is

$y=2x^2+4x-7$

7 0

3 years ago

How do i solve 12×+9=10×1

s2008m [1.1K]

Answer:

Step-by-step explanation:

Unfortunately, your " 12×+9=10×1 " can be interpreted in more than one way. The symbol " × " should be used ONLY to indicate multiplication. Thus, " 12× " reads as ' 12x.' Then we have: 12x + 9 = 10. Unsure of what you meant by " 10×1". So I will treat your "10×1" as simply '10.'

Then we have 12x + 9 = 10, which reduces to 12x = 1 if we subtract 9 from both sides.

12x = 1 yields x = 1/12.

If this is not the result you expected, please go back to the original problem and share it as accurately as you can.

6 0

3 years ago