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3 years ago

Which letter is in the solution set for graph #2

Mathematics

1 answer:

stealth61 [152]3 years ago

8 0

Answer:

Step-by-step explanation:

y > 0 - the region above the line together with that line

y ≥ 0 - the region above the line together with that line

y < 0 - the region below the line without that line

y ≤ 0 - the region below the line together with that line

We have:

y > 2 - the region above the line together with that line

y ≥ 2x - 3 - the region above the line together with that line

<em>look at the picture</em>

The common part is the solution.

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a 9 grade math class has 27 students there are twice as many girls in this class as there are boys.write a system of equation th

Natalka [10]

<span>The first equation is x + y = 27 For the second equation, there are twice as many girls (y) as boys (x), so you write: y = 2x Now you have a system of equations: x + y = 27 y = 2x</span>

8 0

3 years ago

Emily practices piano for 2/3 of an hour on Monday and 1/2 hour on Wednesdays. How many hours does Emily spend practicing piano

Sergeu [11.5K]

Answer:

50 minutes

Step-by-step explanation:

Given:

$\bullet \ \ \text{Monday:} \ \dfrac{2}{3} \times \text{Hour}\\\\\bullet \ \text{Wednesday:} \ \dfrac{1}{2} \times \text{Hour}$

Since Emily only practiced on Monday and Wednesday, the sum of time on both days is the time Emily practiced on the piano for a week.

$\implies \text{Monday + Wednesday = Total time practiced on piano for a week}$

<u>Substitute the times in the equation</u>

$\implies (\dfrac{2}{3} \times \text{Hour}) + (\dfrac{1}{2} \times \text{Hour}) = \text{Total time practiced on piano for a week}$

<u>Simplify the equation</u>

$\implies (\dfrac{2}{3} \times 60 \ \text{minutes}) + (\dfrac{1}{2} \times 60 \ \text{minutes}) = \text{Total time practiced on piano for a week}$

$\implies (20 \ \text{minutes}) + (30 \ \text{minutes}) = \text{Total time practiced on piano for a week}$

$\implies \boxed{50 \ \text{minutes} = \text{Total time practiced on piano for a week}}$

4 0

2 years ago

A tangent from point P to a circle of radius 4 cm is 10 cm long. Find: <br>a the distance of P from the centre of the circle <br

d1i1m1o1n [39]

Answer:

see explanation

Step-by-step explanation:

The tangent and the radius at the point of contact form a right angle

Using Pythagoras' identity on the right triangle formed.

Let x be the distance from the centre to P, then

x² = 4² + 10² = 16 + 100 = 116 ( take the square root of both sides )

x = $\sqrt{116}$ ≈ 10.77 cm (to 2 dec. places )

let the required angle be Θ, then

Using the sine or cosine ratio in the right triangle.

cosΘ = $\frac{adjacent}{hypotenuse}$ = $\frac{10}{\sqrt{116} }$

Θ = $cos^{-1}$ ( $\frac{10}{\sqrt{116} }$ ) ≈ 21.8°

7 0

3 years ago

URGENT NEED HELP FAST LINKS WILL BE REPORTED

dolphi86 [110]

Answer:

model B is shaded to represent 37.5%

here,

=3÷8×100%

=37.5%

7 0

3 years ago

If UV=x+13 and RT=x-37, What is the value of x?

liberstina [14]

Answer:

x = 87

Step-by-step explanation:

the ratio SR / RV is equal the ratio ST / TU (both ratios are equal to 1), and the angle in the vertex S is the same for both triangles SUV and STR, so we can affirm that these triangles are similar (case S-A-S).

Then, we have that the ratio SR / SV is the same as RT / UV:

SR / SV = RT / UV = 1 / 2

RT * 2 = UV

2*(x - 37) = x + 13

2x - 74 = x + 13

x = 87

3 0

4 years ago