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Sergio [31]
3 years ago
6

For the inequality below, write the set of numbers in interval notation.

Mathematics
1 answer:
snow_tiger [21]3 years ago
4 0
The answer would be [4, infinity)
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Can someone please help me fill this out I generally need help
Aneli [31]

Answer:

confusement

Step-by-step explanation:

3 0
3 years ago
Find the area of the rectangleABCD
I am Lyosha [343]

Step-by-step explanation:

take the length of side ab and multiply it by side cd

8 0
3 years ago
1 and 2 are a linear pair, and 2 and 3 are vertical angles. m 2=(5+4 y) and m 3=(6 y-25). what is m 1
poizon [28]
Vertical angles are equal to each other:
        ∠2     =    ∠3
     5 + 4y = 6y - 25
 →      30 = 2y
→       15 = y

∠2 = 5 + 4y = 5 + 4(15) = 5 + 60 = 65

linear pairs equal 180:
     ∠1 + ∠2 = 180
→ ∠1 + 65 = 180
→      ∠1    = 115

5 0
3 years ago
Calculate the area of a circle with the radius of 5cm (1dp)
quester [9]

Answer:

25π ≈ 78.5 cm squared

Step-by-step explanation:

Area of circle= πr²

Substitute: π(5)²

Solution: 25π or about 78.5 cm²

7 0
3 years ago
Ok whoever answers this correct will get 100 brainly points
Snezhnost [94]

Answer:

We are given an area and three different widths and we need to determine the corresponding length and perimeter.  

The first width that is provided is 4 yards and to get an area of 100 we need to multiply it by 25 yards.  This would mean that our length is 25 yards and our perimeter would be 2(l + w) which is 2(25 + 4) = 58 yards.

The second width that is given is 5 yards and in order to get an area of 100 yards we need to multiply by 20 yards.  This would mean that our length is 20 yards and our perimeter would be 2(l + w) which is 2(20 + 5) = 50 yards.

The final width that is given is 10 yards and in order to get an area of 100 yards we need to multiply by 10.  This would mean that our length is 10 yards and our perimeter would be 2(l + w) which is 2(10 + 10) = 40 yards.

Therefore the field that would require the least amount of fencing (the smallest perimeter) is option C, field #3.

<u><em>Hope this helps!</em></u>

3 0
2 years ago
Read 2 more answers
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