The measure of an exterior angle of a regular polygon is 45. What is the interior angle and how many sides?

Ming took a cab across town. His fare was \$22$22, and he leaves an 18\%18% tip. What is the total amount Ming pays the cab driv

Lilit [14]

Answer:

$25.96

Step-by-step explanation:

First, you turn the percent into a decimal, which gives you .18. Then, you multiply $22 by .18. Finally, you add the $3.96 that you get by multiplying $22 by .18, and you get the answer that is above. Plz mark brainliest if correct.

6 0

3 years ago

Read 2 more answers

What is the slope intercept from for 16x+9y=40

Doss [256]

Answer:

$y = (- \frac{16}{9})x + \frac{40}{9}$ is the slope intercept form for 16x+9y=40

Step-by-step explanation:

Here, the given equation is 16 x + 9 y = 40

Now, the slope intercept form of an equation is y = mx + c,

here m = slope of the equation, b = y - intercept

So, now 16x + 9y = 40 on simplification gives

9y = 40 - 16x

or $y = \frac{40 - 16x}{9} = \frac{40}{9} - \frac{16x}{9}$

or, $y = (- \frac{16}{9})x + \frac{40}{9}$ is the slope intercept form of the given equation.

Here, m = (-16/9) and y- intercept = 40/9

7 0

4 years ago

Substitution and elimination

nlexa [21]

Whats The Question ????

3 0

3 years ago

Find the approximate value of the circumference of a circle with the given radius. Use = 3.14. Round your results to one more de

Natali5045456 [20]

C = 2 x 3.14 x 4.6
C = 28.89

answer
C = 28.89 in

5 0

3 years ago

Read 2 more answers

A tire manufacturer is considering a newly designed tread pattern for its all-weather tires. Tests have indicated that these tir

Nataly_w [17]

Answer:

With outlier (102)

$t=\frac{126.2-125}{\frac{9.138}{\sqrt{10}}}=0.415$

$p_v =P(t_{9}>0.415)=0.344$

If we compare the p value and a significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 125 feet at 5% of significance.

Without outlier (102)

$t=\frac{128.89-125}{\frac{3.551}{\sqrt{9}}}=3.285$

$p_v =P(t_{8}>3.285)=0.0056$

And we conclude that we reject the null hypothesis since $p_v$ . So the final conclusion would be not use the method since the value of 102 observed can be a potential outlier, removing this value we see that we reject the null hypothesis and we have a significant result that the true mean is higher than 125.

Step-by-step explanation:

Previous concepts and data given

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Data: 129, 128, 130, 132, 135, 123, 102, 125, 128, 130

We can calculate the mean with the following formulas:

$\bar X =\frac{\sum_{i=1}^n X_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X=126.2$ represent the sample mean

$s=9.138$ represent the sample standard deviation

n=10 represent the sample selected

$\alpha$ significance level

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is significantly higher than 125, the system of hypothesis would be:

Null hypothesis: $\mu \leq 125$

Alternative hypothesis: $\mu > 125$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{126.2-125}{\frac{9.138}{\sqrt{10}}}=0.415$

P-value

First we need to calculate the degrees of freedom given by:

$df=n-1=10-1= 9$

Then since is a right tailed sided test the p value would be:

$p_v =P(t_{9}>0.415)=0.344$

Conclusion

If we compare the p value and a significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 125 feet at 5% of significance.

Using all the data we see that we don;t have enough info to conclude that the true mean is higher than 125, but if we see careful 9 of the 10 values are over the limit of 125 feet. And if we repeat the procedure with the outlier of 102. We got this:

$\bar X=128.89$ represent the sample mean

$s=3.551$ represent the sample standard deviation

$t=\frac{128.89-125}{\frac{3.551}{\sqrt{9}}}=3.285$

First we need to calculate the degrees of freedom given by:

$df=n-1=9-1= 8$

Then since is a right tailed sided test the p value would be:

$p_v =P(t_{8}>3.285)=0.0056$

And we conclude that we reject the null hypothesis since $p_v$ . So the final conclusion would be not use the method since the value of 102 observed can be a potential outlier removing this value we see that we reject the null hypothesis and we have a significant result that the true mean is higher than 125.

8 0

3 years ago