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3 years ago

6

The measure of an exterior angle of a regular polygon is 45. What is the interior angle and how many sides?

1 answer:

Brilliant_brown [7]3 years ago

3 0

Check the picture below.

$\bf \textit{sum of all exterior angles in a polygon}\\\\ n\theta = 360~~ \begin{cases} n=\stackrel{number~of}{sides}\\ \theta =angle~in\\ \qquad degrees\\[-0.5em] \hrulefill\\ 0=45 \end{cases}\implies n(45)=360\implies n=\cfrac{360}{45}\implies \stackrel{\textit{an octagon}}{n=8}$

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Five less than half the distance from Delaney’s home to the mall is more than 6 miles.

vovikov84 [41]

let x = the distance from Delany's house to the mall

so half the distance would be 1/2x

then it is 5 miles less than that so you would subtract 5 to give you 1/2x-5

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5 0

3 years ago

Read 2 more answers

1) Omar has scored 85, 71, and 77 on the first three exams in his math class. If the standard 70,80,90 scale is used for grades

Rus_ich [418]

Answer:

a. 47

b. 87

c. 127

Step-by-step explanation:

Assume a total of 4 exams ( first 3 plus a final)

Let final score be X,

Hence, average score = (85 + 71 + 77 + x) / 4 = (233 + x) / 4

a) to get a C, the average score must be 70

70 = (233 + x) / 4

(233 + x) = 70 (4) = 280

x = 280 - 233 = 47 (Ans)

b) to get a B, the average score must be 80

80 = (233 + x) / 4

(233 + x) = 80 (4) = 320

x = 320 - 233 = 87 (Ans)

c) to get a A, the average score must be 90

90 = (233 + x) / 4

(233 + x) = 90 (4) = 360

x = 360 - 233 = 127 (Ans)

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3 years ago

Please help it’s for a grade I’ll give you Brinley if right

Vikki [24]

Answer: D

Step-by-step explanation:

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3 years ago

what is the volume of a right cylinder which has a base radius of 14 inches and a height of 2 inches?

azamat

The answer is 28 for the volume

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3 years ago

Which expression is equivalent to √48x5, if x> 0?

Lerok [7]

Answer:

C. 4x²√(3x)

Step-by-step explanation:

if x > 0

$\sqrt{48x^{5}} =\sqrt{48} \times \sqrt{x^{5}}$

$=\sqrt{16\times 3} \times \sqrt{x^{4}\times x}$

$=\sqrt{16} \times \sqrt{3} \times \sqrt{x^{4}} \times \sqrt{x}$

$=4\times \sqrt{3} \times \sqrt{\left( x^{2}\right)^{2} } \times \sqrt{x}$

$=4\times \sqrt{3} \times x^{2}\times \sqrt{x}$

$=4\times x^{2} \times \sqrt{3} \times \sqrt{x}$

$=4\times x^{2}\times \sqrt{3x}$

8 0

1 year ago