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2 years ago

Help me please i need help

Mathematics

1 answer:

adell [148]2 years ago

8 0

Answer:

I have NO IDEA

Step-by-step explanation:

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Let P(x) = 3x³-ax+b. If P(1) = P(-1) and P(2)=16, find the values of a and b

kozerog [31]

P(1) = P(-1)

P(1) = 3 - a + b
P(-1) = -3 + a + b

-> 3 - a + b = -3 + a + b
-> 3 - a + b + 3 - a - b = 0
-> 6 - 2a = 0
-> a = 3.

P(2) = 24 - 2a + b -> 24 - (2a - b) = 16 -> 2a - b = 8
-> 6 - b = 8
b = -2.

So, a = 3 and b = -2

Recheck : P(1) = 3 - 3 + (-2) = -2
P(-1) = -3 + 3 + (-2) = -2 => P(1) = P(-1) (true)

P(2) = 24 - 6 + (-2) = 16.

6 0

2 years ago

What is PIE multiplied by PIE?

oksian1 [2.3K]

Pie equal 3.14. So therefore 3.14 x 3.14= 9.8596

6 0

3 years ago

Read 2 more answers

4p-10<6p-8 or 10p+16<9p-3

Finger [1]

Answer:

p>-1 or p<-19

Step-by-step explanation:

4p-10<6p-8 (add 10 to each side)

4p< 6p+2 (subtract 6p from each side)

-2p<2 (divide by -2 and switch the sign)

p>-1

10p+16<9p-3 (subtract 16 from each side)

10p<9p+-19 (subtract 9p from each side)

p<-19

8 0

2 years ago

What is the predicted difference in sleep between individuals A and B, where individual A has 12 years of education and works 20

kari74 [83]

Answer: The predicted difference in sleep is 1251437 minutes.

Step-by-step explanation:

Since we have given that

Number of years of education = 12 years

Number of minutes a week = 2000

As we have

In case of individual A:

7 days = 2000 minutes

1 year = 365 days = $\dfrac{2000}{7}\times 365=104285$

12 years = $104285\times 12=1251420\ minutes$

In case of individual B:

7 days = 3000 minutes

1 year = 365 days = $\dfrac{3000}{7}\times 365=156428$

16 years = $156428\times 16=2502857$ minutes

So, the predicted difference in sleep between individuals A and B is given by

$2502857-1251420\\\\=1251437\ minutes$

Hence, the predicted difference in sleep is 1251437 minutes.

7 0

3 years ago

Blake is playing a racing game on his computer. The game tracks the locations of objects using and y coordinates (see graph belo

Anvisha [2.4K]

<h3>Answer: 2.2 units</h3>

============================================

Explanation:

I'll define these point labels

B = Blake's starting position
F = finish line
C = the third unmarked point of the triangle

The locations of the points are

B = (-8,1)
C = (-6,-3)
F = (4,-2)

Use the distance formula to find the distance from B to C

$B = (x_1,y_1) = (-8,1) \text{ and } C = (x_2,y_2) = (-6,-3)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-8-(-6))^2 + (1-(-3))^2}\\\\d = \sqrt{(-8+6)^2 + (1+3)^2}\\\\d = \sqrt{(-2)^2 + (4)^2}\\\\d = \sqrt{4 + 16}\\\\d = \sqrt{20} \ \text{ ... exact distance}\\\\d \approx 4.47214 \ \ \text{... approximate distance}\\\\$

Segment BC is roughly 4.47214 units long.

Following similar steps, you should find that segment CF is approximately 10.04988 units long.

If Blake doesn't take the shortcut, then he travels approximately BC+CF = 4.47214+10.04988 = 14.52202 units. This is the path from B to C to F in that order.

---------

Use the distance formula again to find the distance from B to F. This distance is about 12.36932 units. He travels this amount if he takes the shortcut.

Subtract this and the previous result we got

14.52202 - 12.36932 = 2.1527

That rounds to 2.2

This is the amount of distance he doesn't have to travel when he takes the shortcut.

In other words, the track is roughly 2.2 units shorter when taking the shortcut.

Side note: Replace "units" with whatever units you're working with (eg: feet or meters).

7 0

2 years ago