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frosja888 [35]
3 years ago
8

32.determine the rate of change of the graph

Mathematics
2 answers:
Anon25 [30]3 years ago
7 0
Rise over run 4/2 or 2 would be the rate of change the equation would be
Y=2x+12 or Y=4/2x+12 either one would work
densk [106]3 years ago
6 0
12, Y=2 X=1, starts at 12, rate is  (12+(2*Y) + (1*X) )
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Fill in the blank. ​_______ are sample values that lie very far away from the majority of the other sample values. Centers Distr
cestrela7 [59]

Answer:

Outliers are sample values that lie very far away from the majority of the other sample values. Centers Distributions Outliers Frequencies are sample values that lie very far away from the majority of the other sample values.

Step-by-step explanation:

4 0
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Find c.<br> C<br> 6.<br> 8<br> C =<br><br> Please help
nataly862011 [7]

Answer:

10

Step-by-step explanation:

We can use the Pythagorean theorem since this is a right triangle

a^2 + b^2 = c^2

8^2 + 6^2 = c^2

64+36 = c^2

100 = c^2

Take the square root of each side

sqrt(100) = sqrt(c^2)

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3 years ago
the top walking deck of a ship is 770 ft long. this is only 14/15 of the length of the ship. how long is the ship?
Yuki888 [10]
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8 0
3 years ago
In right ABC, AN is the altitude to the hypotenuse. FindBN, AN, and AC,if AB =2 5 in, and NC= 1 in.
Rama09 [41]

From the statement of the problem, we have:

• a right triangle △ABC,

,

• the altitude to the hypotenuse is denoted AN,

,

• AB = 2√5 in,

,

• NC = 1 in.

Using the data above, we draw the following diagram:

We must compute BN, AN and AC.

To solve this problem, we will use Pitagoras Theorem, which states that:

h^2=a^2+b^2\text{.}

Where h is the hypotenuse, a and b the sides of a right triangle.

(I) From the picture, we see that we have two sub right triangles:

1) △ANC with sides:

• h = AC,

,

• a = ,NC = 1,,

,

• b = NA.

2) △ANB with sides:

• h = ,AB = 2√5,,

,

• a = BN,

,

• b = NA,

Replacing the data of the triangles in Pitagoras, Theorem, we get the following equations:

\begin{cases}AC^2=1^2+NA^2, \\ (2\sqrt[]{5})^2=BN^2+NA^2\text{.}\end{cases}\Rightarrow\begin{cases}NA^2=AC^2-1, \\ NA^2=20-BN^2\text{.}\end{cases}

Equalling the last two equations, we have:

\begin{gathered} AC^2-1=20-BN^2.^{} \\ AC^2=21-BN^2\text{.} \end{gathered}

(II) To find the values of AC and BN we need another equation. We find that equation applying the Pigatoras Theorem to the sides of the bigger right triangle:

3) △ABC has sides:

• h = BC = ,BN + 1,,

,

• a = AC,

,

• b = ,AB = 2√5,,

Replacing these data in Pitagoras Theorem, we have:

\begin{gathered} \mleft(BN+1\mright)^2=(2\sqrt[]{5})^2+AC^2 \\ (BN+1)^2=20+AC^2, \\ AC^2=(BN+1)^2-20. \end{gathered}

Equalling the last equation to the one from (I), we have:

\begin{gathered} 21-BN^2=(BN+1)^2-20, \\ 21-BN^2=BN^2+2BN+1-20 \\ 2BN^2+2BN-40=0, \\ BN^2+BN-20=0. \end{gathered}

(III) Solving for BN the last quadratic equation, we get two values:

\begin{gathered} BN=4, \\ BN=-5. \end{gathered}

Because BN is a length, we must discard the negative value. So we have:

BN=4.

Replacing this value in the equation for AC, we get:

\begin{gathered} AC^2=21-4^2, \\ AC^2=5, \\ AC=\sqrt[]{5}. \end{gathered}

Finally, replacing the value of AC in the equation of NA, we get:

\begin{gathered} NA^2=(\sqrt[]{5})^2-1, \\ NA^2=5-1, \\ NA=\sqrt[]{4}, \\ AN=NA=2. \end{gathered}

Answers

The lengths of the sides are:

• BN = 4 in,

,

• AN = 2 in,

,

• AC = √5 in.

7 0
1 year ago
Write the equation of a line that goes through the points (-7,9) and (-4,3).
solong [7]

Answer:

y= -2x - 5

Step-by-step explanation:

You have use to slope intercept and formula to get the answer.

3 0
2 years ago
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