Answer:
No, because as the x-values are increasing by a constant amount, the y-values are not being multiplied by a constant amount.
Step-by-step explanation:
We have a set of ordered pairs of the form (x, y)
If a function is exponential then the ratio between the consecutive values of y, is always equal to a constant.
This means that:
\frac{y_2}{y_1}=\frac{y_3}{y_2}=\frac{y_4}{y_3}=by1y2=y2y3=y3y4=b
This is: y_2=by_1y2=by1
Now we have this set of points {(-1, -5), (0, -3), (1, -1), (2, 1)}
Observe that:
\begin{gathered}\frac{y_2}{y_1}=\frac{-3}{-5}=\frac{3}{5}\\\\\frac{y_3}{y_2}=\frac{-1}{-3}=\frac{1}{3}\\\\\frac{3}{5}\neq \frac{1}{3}\end{gathered}y1y2=−5−3=53y2y3=−3−1=3153=31
Then the values of y are not multiplied by a constant amount "b"
Simple. Just add/subtract each term. 4n-2n=2n. 8m+7m=15m.
This is very basic stuff.
Answer:
i'vebeenknowntomissandtellsendgirlstowishingwells
Step-by-step explanation:
ifyou'remymaniwantyoutomyself
Answer:
Step-by-step explanation:
(distribute)
-3x -9 -3x + 3 + 8x = 4
(simplify)
2x -6 = 4
x=5
If f(x) is an odd function, the greatest number of points that can lie in Quadrant II is 1
<h3>How to determine the number of points?</h3>
The given parameters are:
Function f(x) = Odd function
Points in quadrant IV
The number of points in the upper quadrants is:
Upper = 14/2
This gives
Upper = 7
The upper quadrants are I and II
This means that:
I + II = 7
So, we have:
6 + II = 7
Subtract 6 from both sides
II = 1
Hence, the greatest number of points that can lie in Quadrant II is 1
Read more about odd functions at:
brainly.com/question/14192001
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