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Andrews [41]
2 years ago
6

One bag of lawn fertilizer can cover approximately 5,000 square feet. Mike’s lawn is about 500 square feet. When Mike applies fe

rtilizer to his lawn, he applies it to 3/4 of his lawn only. Question: Part B: Mike fertilizes his lawn an average of 4 times per year. About how many full years will he be able to fertilize his lawn with one bag of fertilizer? Write your answer in the space provided.
Mathematics
1 answer:
Dvinal [7]2 years ago
3 0
5,000 - bag of fertilizer
500 - Mike’s lawn
3/4 - applied fertilizer
4 - frequency in 1 year

(500 x 3/4 )x 4
(1500 / 4 ) x 4
1500 sqm / yr

5,000 sqm / 1500sqm/yr
3.33 yr

He will be able to fertilize it in 3 full years
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Please help find them <br>1 AB<br><br>2 BC​
spin [16.1K]

Answer:

AB ≈ 15.7 cm, BC ≈ 18.7 cm

Step-by-step explanation:

(1)

Using the Cosine rule in Δ ABD

AB² = 12.4² + 16.5² - (2 × 12.4 × 16.5 × cos64° )

       = 153.76 + 272.25 - (409.2 cos64° )

       = 426.01 - 179.38

       = 246.63 ( take the square root of both sides )

AB = \sqrt{246.63} ≈ 15.7 cm ( to 1 dec. place )

(2)

Calculate ∠ BCD in Δ BCD

∠ BCD = 180° - (53 +  95)° ← angle sum in triangle

∠ BCD = 180° - 148° = 32°

Using the Sine rule in Δ BCD

\frac{BC}{sin53} = \frac{BD}{sin32} = \frac{12.4}{sin32} ( cross- multiply )

BC × sin32° = 12.4 × sin53° ( divide both sides by sin32° )

BC = \frac{12.4sin53}{sin32} ≈ 18.7 cm ( to 1 dec. place )

         

6 0
2 years ago
Select the two values of x that are roots of this equation.<br> 2x+11x+15= 0
Amiraneli [1.4K]

Answer:

The roots of the equation are x=-3 and x=-2.5

Step-by-step explanation:

<u><em>The correct quadratic equation is</em></u>

2x^2+11x+15=0

we know that

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0 is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

2x^{2} +11x+15=0  

so

a=2\\b=11\\c=15

substitute in the formula

x=\frac{-11(+/-)\sqrt{11^{2}-4(2)(15)}} {2(2)}

x=\frac{-11(+/-)\sqrt{121-120}} {4}

x=\frac{-11(+/-)\sqrt{1}} {4}

x=\frac{-11(+/-)1} {4}

x_1=\frac{-11(+)1}{4}=-2.5

x_2=\frac{-11(-)1}{4}=-3

therefore

The roots of the equation are x=-3 and x=-2.5

5 0
2 years ago
Can you help me guys? Solve the equation.
Jet001 [13]

Answer:

d =  244

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Exponential function f is represented by the table. x -2 -1 0 1 2 f(x) -46 -22 -10 -4 -1 Function g is represented by the equati
Scrat [10]

The statement that describes better about function is "Both functions are increasing, but function g increases at a faster average rate." since option (c) is correct.

Given the table

x         f(x)

-2        -46

-1         -22

0         -10

1           -4

2          -1

We have to choose which statement describes better about function

Let us assume f(x)=ab^x+c

at x=0, f(0)=-10

So, -10 =a+c

Similarly, by satisfying the above table in the f(x)

f(x)=\frac{33}{5} (\frac{1}{11})^x-\frac{17}{5}

f'(x) > 0

So we can say that f(x) is an increasing function.

g(x) = - 18  (\frac{1}{3}  )^ x + 2

g^ \prime (x) = - 18 (\frac{1}{3}  )^ x  ln(1/3)

ln(1/3) < 0

So, g^ \prime (x) > 0

So, g(x) is an increasing function.

For any x∈f(x) and  x∈g(x) g'(x) > f'(x)

So, g increases at a faster average rate

Thus, Both functions are increasing, but function g increases at a faster average rate.

Learn more about increasing functions here: brainly.com/question/12940982

#SPJ10

7 0
1 year ago
Solve xy − 2 = k for x.
MA_775_DIABLO [31]
Isolate x
So xy - 2 = k
Then
xy = k + 2

x = (k+2)/y
6 0
2 years ago
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