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Likurg_2 [28]
3 years ago
10

Using Basic trigonometry

Mathematics
1 answer:
Leno4ka [110]3 years ago
6 0
Csc^2(theta) - 1 is equal to cot^2(theta)

therefore,

tan(theta)*cot^2(theta)

tan(theta)*[cot(theta)*cot(theta)]

[tan(theha)*cot(theta)]*cot(theta)

***tan(theta)*cot(theta) equals 1***

1*cot(theta)

cot(theta) [ANSWER]
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Find the perimeter of quadrilateral ABCD with vertices A(-2,-2), B(-1,3),
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Answer:

<h2> 22.2</h2>

Step-by-step explanation:

Step one

given the coordinates

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AB=(-2,-2),(-1,3)

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The distance between points AB=

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AB= \sqrt (-1+2)^2+(3+2)^2\\\\AB= \sqrt 1^2+(5)^2\\\\AB= \sqrt26\\\\AB=5.1

The distance between points BC=

BC= \sqrt (5+1)^2+(3-3)^2\\\\BC= \sqrt 6^2+(0)^2\\\\BC= \sqrt36\\\\BC=6

The distance between points CD

CD= \sqrt (4-5)^2+(-2-3)^2\\\\CD= \sqrt -1^2+(-5)^2\\\\CD= \sqrt26\\\\CD=5.1

The distance between points DA

DA= \sqrt (4+2)^2+(-2+2)^2\\\\DA= \sqrt 6^2+(0)^2\\\\DA= \sqrt36\\\\DA=6

Hence the perimeter = 5.1+6+5.1+6

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Step-by-step explanation:

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