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sertanlavr [38]
4 years ago
15

547,237 rounded to the nearest 10,000s

Mathematics
1 answer:
bazaltina [42]4 years ago
7 0
I believe the answer would be 500,000
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5x=75 what is the value of x
dezoksy [38]
Solve the problem by doing the following
5x=75
5x/5=75/5
x=15
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3 years ago
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Pleaseeee help it’s due in few
Veseljchak [2.6K]

Answer: i will answer it but you need to make the question bigger

Step-by-step explanation:

6 0
3 years ago
One boat travelling 15 mph goes 47 miles downstream in the same amount of time that another boat going 20 mph goes 40 miles upst
vazorg [7]

Answer:

  3.9 mi/h

Step-by-step explanation:

We assume that the given speeds are the speeds of the boats relative to the water. If c is the speed of the current, we have ...

  time = distance/speed

  47/(15 +c) = 40/(20 -c)

  47(20 -c) = 40(15 +c) . . . . . . multiply by (20-c)(15+c)

  940 -600 = 40c +47c . . . . . add 47c-600

  340 = 87c . . . . . . . . . . . . . . . simplify; next divide by 87

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The speed of the current is about 3.9 mi/h.

6 0
3 years ago
Solve the inequality -x^2-4x+5>0
son4ous [18]
<span><span><span><span>−<span>x2</span></span>−<span>4x</span></span>+5</span>>0</span>
Let's find the critical points of the inequality.<span><span><span><span>
−<span>x2</span></span>−<span>4x</span></span>+5</span>=0</span><span><span><span>
(<span><span>−x</span>+1</span>)</span><span>(<span>x+5</span>)</span></span>=0</span>(Factor left side of equation)<span><span><span><span>
−x</span>+1</span>=<span><span><span>0<span> or </span></span>x</span>+5</span></span>=0</span>(Set factors equal to 0)<span><span>
x=<span><span>1<span> or </span></span>x</span></span>=<span>−5</span></span>
Check intervals in between critical points. (Test values in the intervals to see if they work.)<span>
x<<span>−5</span></span>(Doesn't work in original inequality)<span><span><span>
−5</span><x</span><1</span>(Works in original inequality)<span>
x>1</span>(Doesn't work in original inequality)
Answer: −5<x<1
5 0
3 years ago
no one belongs to both math club and photography club, but the two clubs join to hold a car was. nine member of the math club an
stiv31 [10]
Since there are a total number of 15 members participating, you would divide 150 by 15 since everyone would get their fair share. Next you would multiply 10 by 9 which would result to $90 and the profit the math club received
4 0
4 years ago
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