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3 years ago

PLEASE HELP!! SHOW WORK! <3 Find the area of this figure. Dimensions are in meters.

Mathematics

1 answer:

densk [106]3 years ago

3 0

Answer:

2√46 + 25π/4 ≈ 33.2 . . . . m²

Step-by-step explanation:

The altitude of the triangle is given by the Pythagorean theorem. The right triangle of interest is the one that has 5√2 as its hypotenuse, and a leg of half the base shown. Then the other leg, the altitude of the triangle, is ...

h = √((5√2)² - 2²) = √46

Then the area of the triangle shown is ...

A = (1/2)bh = (1/2)(4)(√46)

A = 2√46

The area of the semicircle is given by the formula ...

A = (1/2)πr²

Filling in the radius shown, the area is computed as ...

A = (1/2)π(5√2/2)² = 25π/4

So, the total area of the figure is ...

total area = triangle area + semicircle area

= 2√46 + 25π/4 . . . square meters

≈ 33.2 . . . square meters

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il63 [147K]

The required value after simplification of the s = -16/3. None of these are correct.

Given that,
To simplify $[\frac{x^{2/3}x^{-1/2}}{x\sqrt{x^3}\sqrt[3]{x}}]^2$ and to find the value of s in $x^s$ .

<h3>What is simplification?</h3>

The process in mathematics to operate and interpret the function to make the function simple or more understandable is called simplifying and the process is called simplification.

Simplification,

$=[\frac{x^{2/3}x^{-1/2}}{x\sqrt{x^3}\sqrt[3]{x}}]^2\\= \frac{x^{4/3}x^{-1}}{x^2x^3*{x}^{2/3}}\\= \frac{x^{1/3}}{x^{17/3}}\\=x^{-16/3}$
Comparing with $x^S$
s = -16/3

Thus, the required value of the s = -16/3. None of these are correct.

Learn more about simplification here: brainly.com/question/12501526

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aleksandrvk [35]

Answer:

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Step-by-step explanation:

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VashaNatasha [74]

Answer:

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Step-by-step explanation:

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