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gladu [14]
3 years ago
11

How to solve this 25 points!!!

Mathematics
1 answer:
jeyben [28]3 years ago
8 0

\mathsf{Given : \dfrac{(3x^2y^-^3)^3}{27(xy)^-^9}}

\mathsf{\implies \dfrac{(3)^3(x^2)^3(y^-^3)^3}{27(x)^-^9(y)^-^9}}

\mathsf{\implies \dfrac{27(x)^6(y)^-^9}{27(x)^-^9(y)^-^9}}

\mathsf{\implies \dfrac{(x)^6}{(x)^-^9}}

\mathsf{\implies x^6^+^9}

\mathsf{\implies x^1^5}

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