Question

How to solve this 25 points!!!

Answer 1

$\mathsf{Given : \dfrac{(3x^2y^-^3)^3}{27(xy)^-^9}}$

$\mathsf{\implies \dfrac{(3)^3(x^2)^3(y^-^3)^3}{27(x)^-^9(y)^-^9}}$

$\mathsf{\implies \dfrac{27(x)^6(y)^-^9}{27(x)^-^9(y)^-^9}}$

$\mathsf{\implies \dfrac{(x)^6}{(x)^-^9}}$

$\mathsf{\implies x^6^+^9}$

$\mathsf{\implies x^1^5}$