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3 years ago

6

Which recursive formula can be used to generate the sequence below, where f(1) = 6 and n ≥ 1?

2 answers:

GaryK [48]3 years ago

6 0

Which recursive formula can be used to generate the sequence below, where f(1) = 6 and n ≥ 1?

f (n + 1) = f(n) + 5

f (n + 1) = f(n) – 5 [this answer is correct]

f (n) = f(n + 1 ) – 5

f (n + 1) = –5f(n)

Rzqust [24]3 years ago

5 0

F(1) = 6
f(2) = 6 - 5 = 1 => f(2) = f(1) - 5

Required recursive formular => f(n + 1) = f(n) - 5

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A rose garden can be planted for $4000. The marginal cost of growing a rose is estimated to $0.30,

wariber [46]

Answer:

$C(x)=4000+0.3x$

$R(x)=1.75x$

$Profit= 1.45x-4000$

Step-by-step explanation:

We are given that A rose garden can be planted for $4000.

The marginal cost of growing a rose is estimated to $0.30,

Let x be the number of roses

So, Marginal cost of growing x roses = $0.3x$

Total cost = $4000+0.3x$

So, Cost function : $C(x)=4000+0.3x$ ---A

Now we are given that the total revenue from selling 500 roses is estimated to $875

So, Marginal revenue = $\frac{\text{Total revenue}}{\text{No. of roses}}$

Marginal revenue = $\frac{875}{500}$

Marginal revenue = $1.75$

Marginal revenue for x roses = $1.75x$

So, Revenue function = $R(x)=1.75x$ ----B

Profit = Revenue - Cost

$Profit= 1.75x-4000-0.3x$

$Profit= 1.45x-4000$ ---C

Now Plot A , B and C on Graph

$C(x)=4000+0.3x$ -- Green

$R(x)=1.75x$ -- Purple

$Profit= 1.45x-4000$ --- Black

Refer the attached graph

6 0

3 years ago

What is the range of this set of data?<br> 111.97, 63, 84, 100, 119,72

Reika [66]

Answer:

56

Step-by-step explanation:

The range of a data set is the difference between the largest and the smallest values in that data set. In this case, the largest value in the data set is 119, and the smallest is 63. 119-63=56, which is the range. Hope this helps!

3 0

3 years ago

Read 2 more answers

Need help with trig!

dedylja [7]

Answer:

1. A. $4.42$

2. F. $20.9$

3. G. $4.57$

4. A. $4.50$

Step-by-step explanation:

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3 years ago

Draw two polygons that have corresponding angles that are all congruent but are not similar to prove that angle congruence is no

Marina86 [1]

There are infinitely many ways to do this. One such way is to draw a very thin stretched out rectangle (say one that is very tall) and a square. Example: the rectangle is 100 by 2, while the square is 4 by 4.

Both the rectangle and the square have the same corresponding angle measures. All angles are 90 degrees.

However, the figures are not similar. You cannot scale the rectangle to have it line up with the square. The proportions of the sides do not lead to the same ratio

100/4 = 25

2/4 = 0.5

so 100/4 = 2/4 is not a true equation. This numerically proves the figures are not similar.

side note: if you are working with triangles, then all you need are two pairs of congruent corresponding angles. If you have more than three sides for the polygon, then you'll need to confirm the sides are in proportion along with the angles being congruent as well.

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3 years ago

If<br>find the values of x and y.

uysha [10]

5-2=3 so x is equal to 3
-3+10 is equal to 7 so y is equal to 10
With this we can conclude that x=3 and y=10
I hope that helps :)

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3 years ago