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MAVERICK [17]
3 years ago
9

A coin is tossed two times, then a month of the year is randomly selected. What is the probability of getting tails each time, a

nd a month that starts with the letter J? I got 1/8 is that correct if not what’s the answer
Mathematics
2 answers:
amm18123 years ago
7 0

Answer:

1/16

Step-by-step explanation:

Given a fair coin, the probability of getting tails on any one toss =

P(tails) = 1/2

if a coin is tossed twice and  we get tails both times,

P( 2 tails on 2 consecutive tosses) = (1/2)(1/2) = 1/4

Total number of months = 12 months

Months that start with J = January, June, July = 3 months

P(selecting months that start with J) = 3/12 = 1/4

Hence the probability of tossing 2 consecutive tails then selecting a month that starts with J

= (1/4) x (1/4)

= 1/16

guajiro [1.7K]3 years ago
5 0

Answer:

1/16

Step-by-step explanation:

1/2 getting tails

1/4 getting tails twice

3/12 getting a J month =1/4

1/4 x 1/4 =1/16

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Based on the fact that Sam goes to the restaurant to buy a burger and a drink and find the value meal price, the marginal cost of the drink is $0.49.

<h3>What is the marginal cost of the drink?</h3>

The fact that Sam is considering buying a burger and chips with the drink being an afterthought means that it is the least important item in the value meal for Sam.

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Full question is:

Sam has decided to buy a burger and fries at a​ restaurant, but he is considering whether to buy a drink as well. Suppose the price of a burger is​ $3.00, fries are​ $1.50, drinks are​ $2.00, and a value meal with all three costs​ $4.99. For​ Sam, what is the marginal cost of the​ drink?

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Which of the following expressions is incorrect?
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-1-121=-12

Step-by-step explanation:

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If the edge length of a cube is 11 feet, what is the correct way to write the expression to represent the volume of the cube in
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g 7. Find Re f and Im f and find their values at the given z. (Both answers should be included) f = z⁄(z + 1), z = 4 − 5
Schach [20]

Answer:

The real and imaginary parts of the result are \frac{1441}{1601} and \frac{4}{1601}, respectively.

Step-by-step explanation:

Let be f(z) = \frac{z}{z+1}, the following expression is expanded by algebraic means:

f(z) = \frac{z\cdot (z-1)}{(z+1)\cdot (z-1)}

f(z) = \frac{z^{2}-z}{z^{2}-1}

f(z) = \frac{z^{2}}{z^{2}-1}-\frac{z}{z^{2}-1}

If z = 4 - i5, then:

z^{2} = (4-i5)\cdot (4-i5)

z^{2} = 16-i20-i20-(-1)\cdot (25)

z^{2} = 41 - i40

Then, the variable is substituted in the equation and simplified:

f(z) = \frac{41-i40}{41-i39} -\frac{4-i5}{41-i39}

f(z) = \frac{37-i35}{41-i39}

f(z) = \frac{(37-i35)\cdot (41+i39)}{(41-i39)\cdot (41+i39)}

f(z) = \frac{1517-i1435+i1443+1365}{3202}

f(z) = \frac{2882+i8}{3202}

f(z) = \frac{1441}{1601} + i\frac{4}{1601}

The real and imaginary parts of the result are \frac{1441}{1601} and \frac{4}{1601}, respectively.

8 0
3 years ago
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