Question 2 (1 point)
1 answer:
You might be interested in
The perimeter, by definition, is the outside measure of that figure. MN and LM are the same length and LK and NK are the same length....we just need to find the lengths! Use the distance formula to find the distance between the 2 points:
For the segment MN, use the coordinates of M as your x1, y1, and use the coordinates of N for x2, y2:
which simplifies to
which is 
So that is the length of both MN and LM. So far our perimeter is
Now let's use the same formula to find out the length of one of the longer segments:
which simplifies down to
which is of course
Since we have 2 of those lengths,
So our perimeter is, in the end,
That's the third choice down
For the segment MN, use the coordinates of M as your x1, y1, and use the coordinates of N for x2, y2:
which simplifies to
So that is the length of both MN and LM. So far our perimeter is
Now let's use the same formula to find out the length of one of the longer segments:
which simplifies down to
which is of course
Since we have 2 of those lengths,
So our perimeter is, in the end,
That's the third choice down
Factor 16 and see the - factor pairs and add them, see which add to -12
-1-16=-17 nope
-2-8=-10 nope
-4-4=-8
hmm
we will solve with math
xy=16
x+y=-12
minus x both sides
y=-12-x
sub for y in other equation
x(-12-x)=16
-12x-x^2=16
add 12x+x^2 both sides
0=x^2+12x+16
use quadratic formula
if you have
ax^2+bx+c=0
x=
0=x^2+12x+16
a=1
b=12
c=16
x=
x=
x=
x=
x=
x=
or 
aprox
x=-1.52786 or -10.4721
those are the numbers
the numbes are -1.52786 or -10.4721
-1-16=-17 nope
-2-8=-10 nope
-4-4=-8
hmm
we will solve with math
xy=16
x+y=-12
minus x both sides
y=-12-x
sub for y in other equation
x(-12-x)=16
-12x-x^2=16
add 12x+x^2 both sides
0=x^2+12x+16
use quadratic formula
if you have
ax^2+bx+c=0
x=
0=x^2+12x+16
a=1
b=12
c=16
x=
x=
x=
x=
x=
x=
aprox
x=-1.52786 or -10.4721
those are the numbers
the numbes are -1.52786 or -10.4721