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Rasek [7]
3 years ago
12

The waiting time at a doctor’s office is uniformly distributed with a minimum waiting time of 10 minutes and a maximum waiting t

ime of 30 minutes. What is the probability that a person has to wait between 10 and 15 minutes?
Mathematics
1 answer:
MariettaO [177]3 years ago
6 0

Answer:

25%

Step-by-step explanation:

There are 20 minutes between 10 and 30 and 5 minutes between 10 and 15 so you need to find 5% of 20 (5/20 x 100) which is 25%

You might be interested in
Jane calculated the circumference of a circle to be 36π. what is the area if the circle
marshall27 [118]

Answer:

103.13

Step-by-step explanation:

A=πr2

C=2πr

A=C2

4π=362

4·π≈103.1324

4 0
3 years ago
Gonzalo observa que el grifo del lavabo de un año después el goteo se produce una velocidad de una gota por segundo y cada gota
Sergio [31]

Answer:

La familia de Gonzalo ha despilfarrado 15,768 litros de agua.

Step-by-step explanation:

Dado que Gonzalo observa que el grifo del lavabo gotea luego de un año, y el goteo se produce una velocidad de una gota por segundo y cada gota contiene 0.5ml de agua, para determinar cuántos litros de agua ha despilfarrado la familia de Gonzalo desde que ellos se dieron cuenta de la avería se debe realizar el siguiente cálculo:

1 año = 365 dias x 24 horas x 60 minutos x 60 segundos

0.5 x 60 x 60 x 24 x 365 = X

30 x 60 x 24 x 365 = X

1800 x 24 x 365 = X

43,200 x 365 = X

15,768,000 = X

15,768,000 / 1000 = X

15,768 = X

Por lo tanto, la familia de Gonzalo ha despilfarrado 15,768 litros de agua.

5 0
3 years ago
PLSSSS HELPPP THANK YOOOUU!!Let f(x) = 3x + 5 and g(x) = 2x - 1 Perform the following function operation (if needed use ^ to mea
jek_recluse [69]

Answer:

I hope it will help you....

5 0
3 years ago
Which relation is a function?
aksik [14]

Answer:

B

Step-by-step explanation:

5 0
3 years ago
(a) Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the prop
zalisa [80]

Answer:

(a) The sample sizes are 6787.

(b) The sample sizes are 6666.

Step-by-step explanation:

(a)

The information provided is:

Confidence level = 98%

MOE = 0.02

n₁ = n₂ = n

\hat p_{1} = \hat p_{2} = \hat p = 0.50\ (\text{Assume})

Compute the sample sizes as follows:

MOE=z_{\alpha/2}\times\sqrt{\frac{2\times\hat p(1-\hat p)}{n}

       n=\frac{2\times\hat p(1-\hat p)\times (z_{\alpha/2})^{2}}{MOE^{2}}

          =\frac{2\times0.50(1-0.50)\times (2.33)^{2}}{0.02^{2}}\\\\=6786.125\\\\\approx 6787

Thus, the sample sizes are 6787.

(b)

Now it is provided that:

\hat p_{1}=0.45\\\hat p_{2}=0.58

Compute the sample size as follows:

MOE=z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})}{n}

       n=\frac{(z_{\alpha/2})^{2}\times [\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})]}{MOE^{2}}

          =\frac{2.33^{2}\times [0.45(1-0.45)+0.58(1-0.58)]}{0.02^{2}}\\\\=6665.331975\\\\\approx 6666

Thus, the sample sizes are 6666.

7 0
3 years ago
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