Adult weighs 12,500 pounds
it is 5 times heavier
baby = x

adult = 5x ( 5 times the weight of the baby)

12,500 = 5x

divide both sides by 5

x = 12500 / 5
x = 2500
the baby weights 2,500 pounds

7 0

3 years ago

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Molly tried to evaluate 93\times5193×5193, times, 51 using partial products. Her work is shown below.

Mrac [35]

Since molly's solution tally's with the given solution, hence Molly's solution is correct.

Given the working on a partial product of 93 and 51 carried out by Molly as shown:

$\begin{array}{llrr} &&93 \\ &&\underline{{}\times51} \\ &\blueD{\text{Step 1}}&\blueD{3}& \blueD{1\times3\text{ ones}}\\ &\greenD{\text{Step 2}}&\greenD{90}& \greenD{1\times 9\text{ tens}}\\ &\maroonD{\text{Step 3}}&\maroonD{150}& \maroonD{50\times 3\text{ ones}}\\ &\goldE{\text{Step 4}}&\underline{{}+\goldE{ 4{,}500}}& \goldE{50\times 9\text{ tens}}\\ &\purpleD{\text{Step 5}}&\purpleD{4{,}743}& \end{array}$

This partial product can also be solved as shown below:

$93 \times 51 = (90+3)\times (50+1)$

Applying the distributive law:

$93 \times 51 = 90(50) + 90(1) + 3(50) + 3(1)\\93 \times 51 =4500 + 90 + 150 + 3\\93 \times 51 =4500+240+3\\93 \times 51 =4740+3\\93 \times 51 =4743$

Since molly's solution tally's with the given solution, hence Molly solution is correct.

Learn more about partial product at: brainly.com/question/24716925

5 0

3 years ago

Identify all of the following solutions of square root of x minus 8 end root plus 8 equals x.

Anit [1.1K]

$\sqrt{x-8} +8=x \\ \sqrt{x-8} =x-8 \\ {( \sqrt{x-8} )}^{2} = {(x-8)}^{2} \\ x-8= x^{2} -16x+64 \\ x^{2} -16x-x+64+8=0 \\ x^{2} -17x+72=0$

$(x-8)(x-9)=0 \\ x-8=0 \ and \ x-9=0 \\ x=8 \ and \ x=9$

4 0

3 years ago

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Write a function rule for the statement. The output is one more than twice the input.

Alina [70]

Dur

1 more than 2 times input
input is x
1 more than twice x
1+2x
f(x)=2x+1

5 0

3 years ago