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2 years ago

10

Challenge 1:

1 answer:

stepan [7]2 years ago

4 0

11+9=20

(11)^2-(9)^2=40

121-81=40

40=40

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If (-2,11)and(9,22) are two anchor points on the trend line, then find the equation of the line

Elza [17]

Answer:

The equation of the line is $y=x+13$

Step-by-step explanation:

step 1

Find the slope

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have

(-2,11) and (9,22)

substitute

$m=\frac{22-11}{9+2}$

$m=\frac{11}{11}$

$m=1$

step 2

Find the equation in slope intercept form

$y=mx+b$

where

m is the slope

b is the y-intercept

we have

$m=1$

$point\ (-2,11)$

substitute in the equation and solve for b

$11=(1)(-2)+b$

$11=-2+b$

Adds 2 both sides

$b=11+2\\b=13$

The equation of the line is

$y=x+13$

4 0

3 years ago

What is the slope of a line through (-3,3) and (-1,1)<br><br> A. 1/2<br> B. 2<br> C. -2<br> D. - 1/2

stealth61 [152]

Answer:

D is the answer

Step-by-step explanation:

8 0

2 years ago

Estou com dificuldade em resolver essa equação do 2° grau por favor façam passo a passso. Eu sei que o resultado e -3, 4. -x²+x+

Elenna [48]

Answer:

-2 plus the added part of -6 eaquals the answer

Step-by-step explanation:

answer is -89

sorry just ned the points

4 0

3 years ago

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yulyashka [42]

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2 years ago