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JulijaS [17]
3 years ago
9

Oliver earns $23.80 an hour. He earns normal rates during week days and time-and-a-

Mathematics
1 answer:
Oxana [17]3 years ago
8 0
So first we calculate the weekly hours:
23.80 x 34 = 809.20

Then we calculate the time and half:
23.80 x 6 x 1.5 = 214.2

Then we total then together:
214.2 + 809.20 = 1023.40
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How would you solve (-1,4),y=3x+5
astraxan [27]

Answer:

y = 12x

Step-by-step explanation:

-1 times 4 equals -4 so you have -4,y = 3x + 5 so you do 5 + 3 so it is 8x then you have -4,y = 8x so you add 4 to each side and it becomes y = 12x

5 0
4 years ago
Two factory plants are making TV panels. Yesterday, Plant A produced 7000 fewer panels than Plant B did. Four percent of the pan
amid [387]

Step-by-step explanation:

17000

Let the number of panels Plant B produced be x.

7000(0.04)+0.02x=620 \\ \\ 0.02x=340 \\ \\ x=17000

8 0
2 years ago
Which statement describes the lines whose equations are y=1/3x+12 and 6y=2x+6
ICE Princess25 [194]
First, you should solve both equations for the same variable. Since the first one is already solved for y, solve the second equation for y as well.

6y = 2x + 6   Divide both sides by 6
y = \frac{1}{3}x + 1

You can see that both lines have a slope of \frac{1}{3}.
Lines that have the same slope are parallel lines.
4 0
3 years ago
What’s the measure of the angle theta?
11111nata11111 [884]

Answer:

∅ = 50°

Step-by-step explanation:

YOU NEED A CALCULATOR TO SOLVE THIS!

You need to use Law of Sines

\frac{a}{sinA} =\frac{b}{sinB} = \frac{c}{sinC}

Here you will be doing \frac{a}{sinA} =\frac{c}{sinC}

a and c are the lengths, while A and C are the angles

\frac{3.46}{sinA} = \frac{2.54}{sin43} you want to get the denominators out from underneath so multiply both sides by sinA and sin43

3.46sin43 = 2.54sinA

Now you want to get sinA alone so divide both sides by 2.54

\frac{3.46sin43}{2.54} = sinA now get A alone

sin^{-1} (\frac{3.46sin43}{2.54}) = A put that into the calculator

49.61741033 = A

7 0
3 years ago
What's the answer for this question? (The numbers after the letters are indexes btw) 27a9 x 18b5 x 4c2 Over 18a4 x 12b2 x 2c
zysi [14]

Answer:

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c

Step-by-step explanation:

Given

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}

Required

Simplify

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}

Cancel out 18

\frac{27a^9 * b^5 * 4c^2 }{a^4 * 12b^2 * 2c}

Divide 4 and 2

\frac{27a^9 * b^5 * 2c^2 }{a^4 * 12b^2 *c}

Divide 27 and 12 by 3

\frac{9a^9 * b^5 * 2c^2 }{a^4 * 4b^2 *c}

Apply law of indices

\frac{9a^{9-4} * b^{5-2} * 2c^{2-1} }{4}

\frac{9a^5 * b^3 * 2c }{4}

Divide 2 and 4

\frac{9a^5 * b^3 * c}{2}

\frac{9a^5b^3c}{2}

Rewrite as:

\frac{9}{2}a^5b^3c

Hence:

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c

4 0
3 years ago
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