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brilliants [131]
2 years ago
6

If F(x)=3x^2-2 find (-3) x f (x)

Mathematics
2 answers:
Ivan2 years ago
4 0

Answer:

-9x²+6

Step-by-step explanation:

f(x)=3x^2-2

g(x)=(-3) x f (x)

  • g(x)= -3*3x²-3*(-2)= -9x²+6
  • g(x)= -9x²+6
lyudmila [28]2 years ago
4 0
The one above is correct I took the test
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lapo4ka [179]
Answer: (-20,-4)

First, you substitute y into the first equation to get 0.01x - 0.3(0.1x - 2) = 1

You then distribute the 0.3 to what is inside the parentheses to get 0.01x-0.03x+0.6=1
(Note: the 0.6 is positive because two negatives multiplied equal a positive)

Now you combine like terms to get -0.02x+0.6=1

Subtract 0.6 from both sides of the equal sign to get -0.02x=0.4

Divide each side by -0.02 to get x=-20

Now plug in -20 to y=0.1x-2 to get y=-4

This gives you the answer (-20,-4)
8 0
3 years ago
Read 2 more answers
Ms. johnson's class is having a pizza party. if there are 14 students and 7 pizzas cut into 8 slices, what answer choice represe
Lubov Fominskaja [6]

We are asked about the fraction of pizza each student gets, so the relevant numbers here is only 14 students and 7 pizzas. SO the fraction of pizza each student get is the ratio of the two:

fraction = 7 pizzas / 14 students

fraction = 1 / 2

 

<span>So each student gets 1/2</span>

8 0
3 years ago
Which expression can be used to find the volume<br> of the rectangular prism in cubic centimeters?
Marysya12 [62]
20,825 because I think you just multiply 245 and 85 and that should be the answer
6 0
3 years ago
What is the midpoint between 2 and 10?
I am Lyosha [343]
The answer to this question would be 6
7 0
3 years ago
In an arithmetic sequence, t4 + t5 + t6 = 300, and t15 +t16+ t17 = 201. Find t18.
stiks02 [169]
In an arithmetic sequence:
Tn=t₁+(n-1)d

t₄=t₁+(4-1)d=t₁+3d
t₅=t₁+(5-1)d=t₁+4d
t₆=t₁+(6-1)d=t₁+5d

t₄+t₅+t₆=(t₁+3d) +(t₁+4d)+(t₁+5d)=3t₁+12d

Therefore:
3t₁+12d=300    (1)


t₁₅=t₁+(15-1)d=t₁+14d
t₁₆=t₁+(16-1)d=t₁+15d
t₁₇=t₁+(17-1)d=t₁+16d

t₁₅+t₁₆+t₁₇=(t₁+14d)+(t₁+15d)+(t₁+16d)=3t₁+45d

Therefore:
3t₁+45d=201    (2)

With the equations (1) and (2) we make an system of equations:

3t₁+12d=300
3t₁+45d=201

we can solve this system of equations by reduction method.

  3t₁+12d=300
-(3t₁+45d=201)
-----------------------------
       -33d=99      ⇒d=99/-33=-3

3t₁+12d=300
3t₁+12(-3)=300
3t₁-36=300
3t₁=300+36
3t₁=336
t₁=336/3
t₁=112

Threfore:

Tn=112+(n-1)(-3)
Tn=112-3n+3
Tn=115-3n

Now, we calculate T₁₈:

T₁₈=115-3(18)=115-54=61

Answer: T₁₈=61




5 0
3 years ago
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