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If FE measures 20 cm, then the area is 314 cm², if BE measure 3.5 cm, then the area is 38.5 cm², if AB measures 11 cm, then the area is 380 cm² and is EF measures 12 cm, then the area is 113 cm².
Area of a circle:
A = π r²
r = 1 /2 of diameter.
FE is the diameter
r = 20 / 2
r = 10 cm
Area of circle using FE:
A = π ( 10 )² = π × 100 = 314 cm²
BE is a radius:
Area = π × 3.5² = π × 12.25 = 38.465
A = 38.5 cm²
AB is a radius:
Area = π × 11²
A = π × 121
A = 379.94 = 380 cm²
EF is a diameter:
r = 12 / 2 = 6 cm
Area = π × 6²
A = π × 36
A = 113.04 = 113 cm²
Therefore, if FE measures 20 cm, then the area is 314 cm², if BE measure 3.5 cm, then the area is 38.5 cm², if AB measures 11 cm, then the area is 380 cm² and is EF measures 12 cm, then the area is 113 cm².
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Your question was incomplete, Please refer the content below:
1) if FE measures 20 centimeters, the approximate area of circle B is what?
2) if BE measures 3.5 centimeters, the approximate area of circle B is what?
3) if AB measures eleven centimeters, the approximate area of circle B is what
4) If EF measures twelve centimeters, the approximate area of circle B is what?
Answer:
The value of c is 12.25
Step-by-step explanation:
we know that
A perfect square trinomial is of the form
In this problem we have
so
equate the equations
we have
the following equations
-----> equation A
and
-----> equation B
<u>Solve the equation A</u>
<u>Solve the equation B</u>
therefore
The value of c is 12.25