-14x + 15y = 15
-14x + 14x + 15y = 14x + 15
15y = 14x + 15
15 15
y = ¹⁴/₁₅x + 1
-21x - 20y = -10
-21x - 20(¹⁴/₁₅x + 1) = -10
-21x - 20(¹⁴/₁₅x) - 20(1) = -10
-21x - 18²/₃x - 20 = -10
-39²/₃x - 20 = -10
+ 20 + 20
-39²/₃x = 10
-39²/₃ -39²/₃
x = ⁻³⁰/₁₁₉
y = ¹⁴/₁₅x + 1
y = ¹⁴/₁₅(⁻³⁰/₁₁₉) + 1
y = ⁻²⁸/₁₁₉ + 1
y = ⁹¹/₁₁₉
(x, y) = (⁻³⁰/₁₁₉, ⁹¹/₁₁₉)
Black line (a) -
x = -2
Purple line (b) -
x = 3
Blue line (c) -
y = 6
Green line (d) -
y = -3
Red line (e) -
Not sure
(7 / 2 ) / 100
3.5 / 100
0.035
So your answer is 0.035
Answer:
a ) y = 1 and x = -1
d) y = 5 and x = -1/2
Step-by-step explanation:
<h2><u>
Substitution method</u></h2><h2><u>Question a</u></h2>
y = x+ 2
y = 2x + 3
<em>we can make the first formula in terms of x , so we can place in into the second formula</em>
y = x + 2
x = y - 2
now put y - 2 where x is in the second equation
y = 2x + 3
y = 2(y - 2) + 3
y = 2y - 4 +3
now solve
4 - 3 = 2y -y
y = 1
since y = 1 we can find what x is by putting into the first formula
y = x +2
x = y - 2
x = (1) -2
x = -1
<h3><u>hence y = 1 and x = -1 </u></h3><h3><u /></h3><h2><u>Question d</u></h2>
y = 2x + 6
y = 4 - 2x
<em>we can make the first formula in terms of x , so we can place in into the second formula</em>
y = 2x + 6
y - 6 = 2x
x = (y-6)/ 2
now place (y-6)/2 where x is in the second formula
y = 4 -2x
y = 4 - 2 (
)
now solve
the multiplication by 2 and division by 2 are cancelled out
hence making the simplified equation as:
y = 4 - y + 6
2y = 4 + 6
2y = 10
y = 5
now place this into the first equation
y = 2x + 6
y - 6 = 2x
x = (y-6)/ 2
x = (5-6)/2
x = -1/2
<h3><u>
hence y = 5 and x = -1/2</u></h3>
Answer:

Step-by-step explanation:
We are given the following in the question:
Let
be the proportion of the internet sales and
be the proportion of the store sale.
Hypothesis:
We have to conduct a hypothesis to check that the Internet sales are more than 10 percent higher than store sales.
Thus, we can design the null and alternative hypothesis as:

Alternate Hypothesis:
The alternate hypothesis states that the proportion of the internet sales is greater than the proportion of store sales by 10 percent.