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3 years ago

Find the solution to the system of equations. y= -5x+6 y=3x-2 x= y=

Mathematics

2 answers:

Neporo4naja [7]3 years ago

8 0

Answer:

x=1, y=1. (1, 1).

Step-by-step explanation:

-5x+6=3x-2

-5x-3x+6=-2

-8x+6=-2

-8x=-2-6

-8x=-8

8x=8

x=8/8

x=1

y=3(1)-2=3-2=1

Ainat [17]3 years ago

4 0

Answer:

X=1 y=1 (1,1)

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In the United States, voters who are neither Democrat nor Republican are called Independent. It is believed that 11% of voters a

Radda [10]

Answer:

a) 0.0214 = 2.14% probability that none of the people are Independent.

b) 0.8516 = 85.16% probability that fewer than 6 are Independent.

c) 0.8914 = 89.14% probability that more than 2 people are Independent.

Step-by-step explanation:

For each people, there are only two possible outcomes. Either they are independent, or they are not. For each person asked, the probability of them being Independent voters is the same. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

It is believed that 11% of voters are Independent.

This means that $p = 0.11$

A survey asked 33 people to identify themselves as Democrat, Republican, or Independent.

This means that $n = 33$

A. What is the probability that none of the people are Independent?

This is P(X = 0). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{33,0}.(0.11)^{0}.(0.89)^{33} = 0.0214$

0.0214 = 2.14% probability that none of the people are Independent.

B. What is the probability that fewer than 6 are Independent?

This is

$P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{33,0}.(0.11)^{0}.(0.89)^{33} = 0.0214$

$P(X = 1) = C_{33,1}.(0.11)^{1}.(0.89)^{32} = 0.0872$

$P(X = 2) = C_{33,2}.(0.11)^{2}.(0.89)^{31} = 0.1724$

$P(X = 3) = C_{33,3}.(0.11)^{3}.(0.89)^{30} = 0.2202$

$P(X = 4) = C_{33,4}.(0.11)^{4}.(0.89)^{29} = 0.2041$

$P(X = 5) = C_{33,5}.(0.11)^{5}.(0.89)^{28} = 0.1463$

$P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.0214 + 0.0872 + 0.1724 + 0.2202 + 0.2041 + 0.1463 = 0.8516$

0.8516 = 85.16% probability that fewer than 6 are Independent.

C. What is the probability that more than 2 people are Independent?

This is:

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{33,0}.(0.11)^{0}.(0.89)^{33} = 0.0214$

$P(X = 1) = C_{33,1}.(0.11)^{1}.(0.89)^{32} = 0.0872$

$P(X < 2) = 0.0214 + 0.0872 = 0.1086$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.1086 = 0.8914$

0.8914 = 89.14% probability that more than 2 people are Independent.

8 0

2 years ago

The equation of the line CD is (y-3)=-2(x-4). what is the scope of the line perpendicular to line CD

Delicious77 [7]

Answer:

y=-1/2x-5

Step-by-step explanation:

First we need to put (y-3)=2(x-4) in slope intercept form.

we need to do order of operations....

so we need to first do the parenthesis

x*2= 2x

2*-4= -8

y-3=2x-8

add 3 on both sides to isolate y

y= 2x-5

so now we know the y=mx+b form

this is one line...

now we need to find out what line is perpendicular.

Perpendicular lines have opposite reciprocals slopes.

y=-1/2x-5

8 0

3 years ago

What makes the statement true? 8^-2=?

GREYUIT [131]

I think the correct answer would be 1/64. <span>A </span>negative exponent<span> just means that the base is on the wrong side of the fraction line, so you need to flip the base to the other side. It is calculated as follows:

8^-2 = 1/8^2 = 1/64

Hope this answers the question. Have a nice day.</span>

6 0

3 years ago

Read 2 more answers

Through (2,6) and perpendicular to y=-5/4x+1

Diano4ka-milaya [45]

1.26
in A decimal
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4 0

3 years ago

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Matrices C and D are shown below.

yKpoI14uk [10]

Answer: