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Finger [1]
3 years ago
5

If $500 is put into a savings account at 9% interest compounded continuously, how much will it be worth at the end of 3 years? H

ow many years will it take to double in value?

Mathematics
1 answer:
Digiron [165]3 years ago
7 0

Answer:

$654.98

Around 7.7 years

Step-by-step explanation:

Value = P × e^(rt)

= 500 × e^(0.09×3)

= 500 × e^(0.27)

= 654.9822254

Double: 500 × 2 = 1000

1000 = 500 × e^(0.09t)

e^(0.09t) = 2

Use ln both sides

0.09t × lne = ln2

t = ln2 ÷ 0.09

t = 7.70163543

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After you subtract both sides by 4. How can you solve for 3x in this equation?
Nataly [62]

Answer:

B

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8 0
4 years ago
According to the Rational Root Theorem, which function has the same set of potential rational roots as the function g(x) = 3x^5
nata0808 [166]

Answer:

The correct option is A.

Step-by-step explanation:

The question is:

According to the Rational Root Theorem, which function has the same set of potential rational roots as the function g(x) = 3x5 – 2x4 + 9x3 – x2 + 12?

A).f(x) = 3x5 – 2x4 – 9x3 + x2 – 12

B).f(x) = 3x6 – 2x5 + 9x4 – x3 + 12x

C).f(x) = 12x5 – 2x4 + 9x3 – x2 + 3

D).f(x) = 12x5 – 8x4 + 36x3 – 4x2 + 48

Solution:

The function given to us is:

3x5 – 2x4 + 9x3 – x2 + 12

Find the factors of 12 and consider it as 'p'

The factors of 12 are:

p = +/- 1 , +/-2 , +/-3 , +/- 4 , +/-6

Now find the factors of 3 and consider it as 'q'

The factors of 3 are:

q = +/- 1 , +/- 3

We know that we write rational terms in p/q form.

Therefore the Rational roots are given by p/q

+/- 1 , +/-2 , +/-3 , +/- 4 , +/-6 , +/- 1/3 , +/- 2/3 , +/- 4/3

Now we will solve the first function given in part A.

f(x) = 3x^5 – 2x^4 - 9x^3 + x^2 - 12

Again find the factors of 12 and consider it as 'p'

The factors are:

p = +/- 1 , +/-2 , +/-3 , +/- 4 , +/-6

Now find the factors of 3 and consider it as 'q' .

q = +/- 1 , +/- 3

Rational root are given by p/q

+/- 1 , +/-2 , +/-3 , +/- 4 , +/-6 , +/- 1/3 , +/- 2/3 , +/- 4/3

Therefore the rational roots of the given function matches the rational roots of the given equation.

Hence the correct option is A

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3 years ago
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HELP I'M SOOOOOO ANGRYYYYY PLEASE HELPPPP<br>determine the values of X for which g(x) is defined​
tiny-mole [99]

Answer: Any real number x as long as x \ne 0 and x \ne -\frac{2}{3}

In other words, anything but 0 or -2/3 is valid.

========================================================

Explanation:

Set the denominator equal to zero and solve for x

2(3x^2 + 2x) = 0

3x^2 + 2x = 0

x(3x + 2) = 0

x = 0 or 3x+2 = 0 .... zero product property

x = 0 or 3x = -2

x = 0 or x = -2/3

If either x = 0 or x = -2/3, then the denominator 2(3x^2 + 2x)  will be zero. But recall that we cannot have zero in the denominator. Dividing by zero is not allowed. The expression is undefined when we divide by zero.

Therefore, we must exclude x = 0 and x = -2/3 from the domain. Any other real number is valid as an x input.

7 0
3 years ago
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