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Valentin [98]
4 years ago
10

Bernie is the manager of the basketball team. He counted that 12 of their 30 basketballs needed to be inflated. What % of the ba

sketballs needed to be inflated?
pls explain
Mathematics
1 answer:
alukav5142 [94]4 years ago
8 0

Answer:

40%

Step-by-step explanation:

12/30 is the same thing of finding the percent.

Do 12/30 to get 0.4

0.4 in percent form is 40%

Hope it Helps!

(Plz Mark Me As Brainliest After Second Answerer)

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Step-by-step explanation:

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3 years ago
The frequency table shows how many visits to the library students in a school have made in the last month.
vfiekz [6]
<h3>Answer:  2.8</h3>

=======================================================

Explanation:

Multiply each visit count with their corresponding frequency.

Examples:

  • 0*12 = 0 for the first row.
  • 1*366 = 366 for the second row
  • 2*53 = 106 for the third row

and so on...

I recommend making a third column like this

\begin{array}{|c|c|c|} \cline{1-3}\text{Visits} & \text{Frequency} & \text{Visits*Frequency}\\\cline{1-3}0 & 12 & 0\\\cline{1-3}1 & 366 & 366\\\cline{1-3}2 & 53 & 106\\\cline{1-3}3 & 52 & 156\\\cline{1-3}4 & 155 & 620\\\cline{1-3}5 & 243 & 1215\\\cline{1-3}\end{array}

That way you can keep track of all the results in an organized way.

Then add everything in the third column

0+366+106+156+620+1215 = 2463

Divide this sum over the total frequency (12+366+53+52+155+243 = 881) and we'll get the mean

2463/881 = 2.7956867

Rounding to one decimal place gets us to 2.8 as the final answer.

-------------

The much longer way to do this is to imagine 12 copies of "0", 366 copies of "1", 53 copies of "2", and so on. We'll have an extremely large data set of 881 items inside it. As you can see, this second method is definitely not recommended to actually carry out. Rather it's helpful to have this as a thought experiment to see why we revert to multiplication instead.

Eg: Imagine adding 155 copies of "4". A shortcut is to simply say 4*155 = 620

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2 years ago
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