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Fynjy0 [20]
4 years ago
14

Shaquil needs to borrow $400. The loan company charges him $80 in fees for the loan. Shaquil calculates that the annual percenta

ge rate (APR) on his loan is 250%. Approximately what is the term of Shaquil’s loan? a. 7 days b. 29 days c. 46 days d. 73 days
Mathematics
2 answers:
lesya [120]4 years ago
6 0

Answer:

(B)  

Step-by-step explanation:

PRINCIPAL AMOUNT(p) = $400

RATE (r)= 250% = 2.5

INTEREST = $80

t = time (in days) = t/365

By using the formula,

r = \frac{i}{pt}

2.5 = \frac{80*365}{400*t}

t = \frac{364*80}{400*2.5}

t = 29.2

t = 29 days (approx)

Hence option (B) is correct.


mina [271]4 years ago
6 0
The answer is B.) 29 Days
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Step-by-step explanation:

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Dave has 10 poker chips, 6 of which are red and the other 4 of which are white. Dave likes to stack his chips and flip them over
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The number of 10 chips stacks that Dave can make if two stacks are not considered distinct is 110.

The solution

To get the symmetric stacks, one has to subtract the symmetric stacks to know the ones that are asymmetric.

The symmetric are flipped. Given that they are double counted what we have to do is to divide through by 2.

6/2 = 3

10/2 = 5

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1/2(10C6) - (5C3) + (5C3)

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3 years ago
Solve for kkk. \dfrac{k}4+ 3= 14 4 k ​ +3=14
masha68 [24]

Answer: k=1

Step-by-step explanation:

Simplify   1/k

    3     2         1

 (((—+2)-(—•k))-4)-(—-2)  = 0

    k     k         k

2.1   Subtracting a whole from a fraction

      2     2 • k

   2 =  —  =  —————

        1       k  

2.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

1 - (2 • k)     1 - 2k

———————————  =  ——————

     k            k  

Simplify  2/k

 3     2        (1-2k)

 (((—+2)-(—•k))-4)-——————  = 0

    k     k          k  

Simplify 3/k

  3     2        (1-2k)

 (((—+2)-(—•k))-4)-——————  = 0

    k     k          k  

5.1   Adding a whole to a fraction

 3                      (1 - 2k)

 (((— +  2) -  2) -  4) -  ————————  = 0

    k                         k    

6.1   Subtracting a whole from a fraction

        2     2 • k

   2 =  —  =  —————

        1       k  

7.1   Subtracting a whole from a fraction

3 + 2 • k     2k + 3

—————————  =  ——————

    k           k  

8.1       Adding fractions which have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

        2     2 • k

   2 =  —  =  —————

        1       k  

9.1     Pull out like factors :

  2 - 2k  =   -2 • (k - 1)

10.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

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The equation now takes the shape :

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Equations which are never true:

10.2      Solve :    -2   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation:

10.3      Solve  :    k-1 = 0

Add  1  to both sides of the equation :

                     k = 1

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